Latest Elitmus Aptitude Question SOLUTION: there r 9 balls and r placed in 3 boxes such that there should be atleast 2 balls in each box find the no of ways

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there r 9 balls and r placed in 3 boxes such that there should be atleast 2 balls in each box find the no of ways

Asked In Elitmus aquib aslam (9 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

zoha khan  (9 years ago)

following combination of balls is possible:
1). 2,2,5 which can be arranged in 3!/2! ways.
2) .2,3,4 which can be arranged in 3! ways.
3). 3,3,3
so total no of ways=3!/2!+3!+1=10 ways.

Is this solution Helpfull? Yes (37) | No (2)  

Pratik Mishra  (9 years ago)

first place 2 balls in each boxes
so, remaining 3 balls placed in (3+3-1)C(3-1) way =10

Is this solution Helpfull? Yes (14) | No (1)  

Arun Kumar Tiwari  (9 years ago)

10 ways....

2,2,5
2,5,2
5,2,2
2,3,4
2,4,3
4,2,3
4,3,2
3,2,4
3,4,2
3,3,3

Is this solution Helpfull? Yes (13) | No (2)  

ASHISH MUKHERJEE  (9 years ago)

according to question 2 balls in each so 6 ball out of the 9 balls.
now reaming 3 ball can placed in any box so for that no of ways is :-
3+3-1c3-1 =5c2 = 10 ways.

Is this solution Helpfull? Yes (5) | No   

VIVEK SINHA  (9 years ago)

First take 6 balls and put two in each box, So no of ways=1
remaining Three can be placed in any pattern i.e can be zero in one or two boxes.
No. of ways=1*(3+3-1C3-1)=5C3=10 ways (Using formula n+r-1Cr-1).

Is this solution Helpfull? Yes (3) | No   

Amit Pal  (9 years ago)

there are 9 balls .. and in three box each contain atleast 2 balls means minimum total no. of ball required=6 and so selection of balls contain 6,7,8,9 balls.
for 6 balls.....
2,2,2
for 7 balls......
2,2,3
2,3,2
3,2,2
for 8 balls.....
2,2,4
2,4,2
4,2,2
2,3,3
3,2,3
3,3,2
for 9 balls.......
2,2,5
2,5,2
5,2,2
2,3,4
2,4,3
4,2,3
3,2,4
3,4,2
4,3,2
3,3,3
so total no. of possible ways=20

Is this solution Helpfull? Yes (2) | No (18)  

kunal dey  (9 years ago)

first we put 2 balls in each box.
now we have 3 balls. we can put balls in 3 boxes any box can get any no. of balls.
1st can put in 3ways in same way we can put 3 balls in 3 box=3*3*3=27

Is this solution Helpfull? Yes (2) | No (5)  

Aditya Kumar  (9 years ago)

firstly put 2 ball in each...2+2+2=6.......(because atleast 2 ball in each)
now remaining ball we have 3 so we can put these 3 ball in 3^3 way
i.e....3*3*3=27
total ways=1+27=28

Is this solution Helpfull? Yes (2) | No (2)  

RAVISH KUMAR  (9 years ago)

ans:- 288

no of ways of placing 2 or more balls in three boxes=4!*3!*2!=288

Is this solution Helpfull? Yes | No (3)  

Anuj Awasthi  (8 years ago)

5c3 ways we can do arrange

Is this solution Helpfull? Yes | No   

Ridam  (4 years ago)

first of all put 2 balls in each box so total ball in the box is 6 and the ball left is 3.Now distribute balls in these box in such a way that any box can get any no. of balls which is given by formula (n+r-1)C(r-1) where n=3 becoz 3 balls left and r=3 ,no. of boxes .so by putting these value we get
5C2=10

Is this solution Helpfull? Yes | No   

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