Latest Elitmus Aptitude Question SOLUTION: 2nd nov 2014 cryptography ______V I A ______G O T -------------- ____G R O T __A A R O * A I A G * * -------------- A S T A R T

______5 7 1
______3 2 6
------------------
____3 4 2 6
__1 1 4 2 *
1 7 1 3 * *
-------------------
1 8 6 1 4 6

Hint

A*T=T
A*O=O
A*G=G
this can only be possible when A=1.now
VIA*O=AARO. u can easily solve this problem

is there any book for solving cryptography question ? i am going to write elitmus exam so please refer any book or link in my mail id "kingrakesh0467@gmail.com" . your response will be highly appriceated.

A*T=T
A*O=O
A*G=G
this can only be possible when A=1
put a = 1 then first assume the value of O which cannot be 0,1 so take it 2 THIS WILL LOOK LIKE

V I 1
G O T
--------------
G R O T
1 1 R O *
1 I 1 G * *
--------------
1 S T 1 R T

NOW ASSUME THE VALUE OF O FIRST RATHER THAN T OR G IT WILL HELP WHILE SOLVE U
SO O CANNOT BE 0 OR 1 SO TAKE IT AS 2 AND REPLACE IN THE Q

V I 1
G 2 T
--------------
G R 2 T
1 1 R 2 *
1 I 1 G * *
--------------
1 S T 1 R T
SINCE T CANNOT BE MORE THAN 9 SO THERE IS NO CARRY HENCE R WILL DEFINATELY BE 4 REPLACE IT

V I 1
G 2 T
--------------
G 4 2 T
1 1 4 2 *
1 I 1 G * *
--------------
1 S T 1 4 T

SINCE THERE IS NO CARRY FROM 2+2 S0 4+4+G =1 ONLY WHEN G IS 3 REPLACE IN Q

V I 1
3 2 T
--------------
3 4 2 T
1 1 4 2 *
1 I 1 3 * *
--------------
1 S T 1 4 T

SINCE 4+4+3 IS GIVING A CARRY SO T MUST BE 6
HENCE REPLACE ALL VALUES
V I 1
3 2 6
--------------
3 4 2 6
1 1 4 2 *
1 I 1 3 * *
--------------
1 S 6 1 4 6
NOW REST U CAN SOLVE AS V I T *6 = 3 4 2 6 WHICH MEANS V I MUST BE 5,7 RESPECTIVELY

HENCE FURTHER SOLVING THIS IT WILL LOOK LIKE THIS

5 7 1
3 2 6
--------------
3 4 2 6
1 1 4 2 *
1 7 1 3 * *
--------------
1 S 6 1 4 6

HAVE U GOT IT

how to solve easily ? pls tell me

guys before starting crypt problems u have to remember some key points.
1. no two alphabets have same number.
2. number values lie between 0 to 9.

now looking at the problem .
VIA*T = GROT.
VIA*O = AARO.
VIA*G = AIAG.
Now basic maths.
1*2=2.
1*3=3.
1*4=4.
f.ex VIA*T=GROT.
this can be only possible when A=1.
now we have value of A.
we can proceed further.
now look at this .
VIA*O=AARO.
for simplicity write it as.
A*O=O.
CARRY+(I*O)=R.
CARRY+(V*O)=AA.
Now
A=1. put value of O=2.
carry=0.
I*O=R.
now focus on this.
CARRY+V*O=AA.
_______+V*2=11.
this can only be possible when
v=5. and the carry generated I*O=R. is 1.
1+5*2=11
v=5,O=2,A=1.
now
I*O=R.
7*2=14. R=4. carry=1.
now er have
A=1
O=2.
I=7.
R=4.
V=5.
now we can solve it easily

571
326
_____________________
3426
1142
1713
__________________
186146
.
guys i know its a little bit complicated. u can learn crypt only by practise.
if anyone had problem contact on me.
I am willing to help anyone .
Wish u happy learning.
https://www.facebook.com/virgo7101

5 7 1
3 2 6
----------------------
3 4 2 6
1 1 4 2 *
1 7 1 3 * *
-----------------------------
1 8 6 1 4 6

______V I A
______G O T
--------------
____G R O T
__A A R O *
A I A G * *
--------------
A S T A R T

T*A = T
O*A = O
G*A= G

==> A MUST BE 1
REPLACE A WITH 1

______V I 1
______G O T
--------------
____G R O T
__1 1 R O *
1 I 1 G * *
--------------
1 S T 1 R T

OBSERVE MULTIPLES OF
V I A * O = A A R O
REPLACE IT WITH
V I 1 * O = 1 1 R O
THIS CASE SATISFY ONLY WHEN O*? = GREATER THAN 10
==> 5 I 1 * 2 = 10 ? 2
BUT WE WANT 11 IN PLACE OF 10 SO CHECK FOR VALUE OF I
5 6 1 * 2 = 1 1 2 2
THIS IS NOT SATISFY THE CONDITION BECAUSE I != O
LETS TRY WITH 5 7 1 * 2 = 1 1 4 2

SO WE GOT THE VALUES V=5, I=7, R=4 & O=2

REPLACE THE GIVEN PUZZLE WITH THEIR VALUES


______5 7 1
______G 2 T
--------------
____G 4 2 T
__1 1 4 2 *
1 7 1 G * *
--------------
1 S T 1 4 T

SIMILARLY CONSIDER 3RD MULTIPLIERS

5 7 1 * G = 1 7 1 G

BY TRIAL AND ERROR METHOD WE GET G=3

5 7 1 * 3 = 1 7 1 3

REPLACE THE PUZZLE WITH THEIR VALUES

______5 7 1
______3 2 T
--------------
____3 4 2 T
__1 1 4 2 *
1 7 1 3 * *
--------------
1 S T 1 4 T

SIMILARLY CONSIDER 1ST MULTIPLIER

5 7 1 * T = 3 4 2 T

BY TRIAL AND ERROR METHOD WE GET T=6

REPLACE THE PUZZLE WITH THEIR VALUES

______5 7 1
______3 2 6
--------------
____3 4 2 6
__1 1 4 2 *
1 7 1 3 * *
--------------
1 S 6 1 4 6

SO FINALLY 1+7 = 8=S

SO THE VALUES OF THIS CRYPTARITHAMATIC PUZZLE IS...

V=5, I=7, A=1, G=3, O=2, T=6, R=4, & S=8.


tHANL

571
*326
.....................
3426
1142
1713
.......................
18646

571*326=186146

Atul please help me to solve this......I m new in crypt.
VIA*O=AARO

sumit yr mera aaj 9 nov ko exam hai. evening me detail me bataunga :)

can u please explain the problem solution completely

571
* 326
-------------
3426
+ 1 142 *
+ 1713 **
------------------
186146

A=1
O=2
V=5
R=4
I=7
G=3
S=8
T=6

571
*326
--------------------
4326
1142
1713
----------------
186146
----------------