Latest Infosys Aptitude Question SOLUTION: An escalator is descending at constant speed.A walks down and takes 50 steps to reach the bottom.B runs down and takes 90 steps in the same time as A takes 10 steps.How many steps

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An escalator is descending at constant speed.A walks down and takes 50 steps to reach the bottom.B runs down and takes 90 steps in the same time as A takes 10 steps.How many steps are visible when the escalator is not operating?

Asked In Infosys (12 years ago)

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GORAKALA THARAKESWARA RAO  (7 years ago)

Lets suppose that A walks down 1 step / min and
escalator moves n steps/ min
It is given that A takes 50 steps to reach the bottom
In the same time escalator would have covered 50n steps
So total steps on escalator is 50 + 50n.
Again it is given that B takes 90 steps to reach the bottom and time
taken by him for this is equal to time taken by A to cover 10 steps i.e
10 minutes. So in this 10 min escalator would have covered 10n steps.
So total steps on escalatro is 90 + 10n
Again equating 50 + 50n = 90 + 10n we get n = 1
Hence total number of steps on escalator is 100.

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vijay  (9 years ago)

visible steps when not operating = n
escalator speed = s
steps taken by A to reach the bottom = 50
steps taken by B to reach the bottom = 90 + (50 - 10) = 130

When walking down, time taken = (n - 50) / s
When running down, time taken = (n - 130) / s

[(n - 50) / s] : [(n - 130) / s] = 5 : 1
(n - 50) : (n - 130) = 5 : 1
(n - 50) * 1 = (n - 130) * 5
n - 50 = 5n - 650
n - 50 - n + 650 = 5n - 650 - n + 650
4n = 600
n = 150

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