Latest IBM Aptitude Question SOLUTION: If a car starts from A towards B with some velocity.Due to some problem in the engine after travelling 30km, the car goes with 4/5 th of its actual velocity.The car reaches B 45 mi

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If a car starts from A towards B with some velocity.Due to some problem in the engine after travelling 30km, the car goes with 4/5 th of its actual velocity.The car reaches B 45 min later to the actual time.If the car engine fails ofter travelling 45km, the car reaches the destination B 36 min late to the actual time.What is the initial velocity of car and what is the distance between A and B in km

Solution

Let the distance between A and B is x and the velocity initially is v
then according to the given conditions
[30/v]+[(x-30)/(4v/5)] = [x/v]+3/4 here 3/4 is for 45 minute
[45/v]+[(x-45)/(4v/5)] = [x/v]+3/5 here 3/5 is for 36 minute
on solving we will get (x-30)/v = 3 and (x-45)/v = 12/5
or x-30 = 3v and x-45 = 12v/5 or x = 105 and v = 25

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Asked In IBM (12 years ago)

Solved Read Solution (2)

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skk  (7 years ago)

20 and 130

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uthra murugesan  (8 years ago)

30/v]+[(x-30)/(4v/5)] = [x/v]+3/4 here 3/4 is for 45 minute
[45/v]+[(x-45)/(4v/5)] = [x/v]+3/5 here 3/5 is for 36 minute
on solving we will get (x-30)/v = 3 and (x-45)/v = 12/5
or x-30 = 3v and x-45 = 12v/5 or x = 105 v=50

Is this solution Helpfull? Yes (1) | No (1)  

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