Latest IBM Aptitude Question SOLUTION: A fires 8 shots to B's 5 but A kills only once in 6 shots while B kills once in 1 shots. When B has missed 87 times, A has killed ?

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A fires 8 shots to B's 5 but A kills only once in 6 shots while B kills once in 1 shots. When B has missed 87 times, A has killed ?

Asked In IBM (12 years ago)

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srilatha  (12 years ago)

A kills only once in 6 shorts and B kills once in 1 shot
let:total shots are 100
when B has missed 87,then B kills 100-87=13
A kills only once in 6 shots so 13/6=2
so when B has missed 87 times at that time A has killed 2 only

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Mukesh Kumar  (7 years ago)

Let the total number of shots be x. Then,
Shots fired by A = 8x/13
Shots fired by B = 5x/13
Killing shots by A = 1/5 of 8x/13= 8x/65
Shots missed by B = 1 of 5x/13 = 5x/13

5x/13 = 87 of x = 87*13/5= 226.
A=8*226/13 = 139.Ans

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Saptarshi Das  (7 years ago)

B missed 87 shots, so totally fired 174 shots, as B kills once in 1 shot which means B kills in every alternate shot.
for B's 174 shots, A would fire 280 (approx) shots.
Now A kills once in 6 shots, i.e every 7th shot by A is a killing shot.
So A kills 40 (Answer)

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