Latest GENPACT Aptitude Question SOLUTION: Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:

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(#M40005020) GENPACT Numerical Ability question Pipes & cisterns Keep an EYE

Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:

A. 6 hours
B. 20/3hours
C. 7 hours
D. 15/2hours

Asked In GENPACT (12 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

Mela Giri  (8 years ago)

Taking the lcm(12,15,20) = 60 liters (capacity of the tank)
In 1 hr : A can fill 5 liters(60/12), B = 4 liters C = 3 liters
Its given that A is open all time and B & C alternately.
So in 1st hr : A+B = 9 liters
2nd hr : A+C = 8 liters
3rd hr : A+B = 9 liters
4th hr : A+C = 8 liters
5th hr : A+B = 9 liters
6th hr : A+C = 8 liters
7th hr : A+B = 9 liters
Total = 60 liters (Capacity of the tank).
So Ans = C. 7 hours.

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chandan partap singh  (11 years ago)

(A + B)'s 1 hour's work = 1 + 1 = 9 = 3 .
12 15 60 20
(A + C)'s hour's work = 1 + 1 = 8 = 2 .
12 20 60 15
Part filled in 2 hrs = 3 + 2 = 17 .
20 15 60
Part filled in 6 hrs = 3 x 17 = 17 .
60 20
Remaining part = 1 - 17 = 3 .
20 20
Now, it is the turn of A and B and 3 part is filled by A and B in 1 hour.
20
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.

Is this solution Helpfull? Yes (4) | No (11)  

Swathi  (8 years ago)

(A + B)'s 1 hour's work = 1 + 1 = 9 = 3 .
12 15 60 20
(A + C)'s hour's work = 1 + 1 = 8 = 2 .
12 20 60 15
Part filled in 2 hrs = 3 + 2 = 17 .
20 15 60
Part filled in 6 hrs = 3 x 17 = 17 .
60 20
Remaining part = 1 - 17 = 3 .
20 20
Now, it is the turn of A and B and 3 part is filled by A and B in 1 hour.
20
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.

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