Latest Elitmus Aptitude Question SOLUTION: a,b,c,d are prime number. how many combintion of prime numbers can be possible such that the sum of two digit(a+b,a+c,a+d,....)..And the sum in increasing order are 2,4,6,8... opt

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(#M40058950) ELITMUS Numerical Ability question number system Keep an EYE

a,b,c,d are prime number. how many combintion of prime numbers can be possible such that the sum of two digit(a+b,a+c,a+d,....)..And the sum in increasing order are 2,4,6,8...

option-- 1 only 2 only 4 only more than 4

Asked In Elitmus kamal (9 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

ashu kaushal  (9 years ago)

2 only is right
2,3,5,7,11,13,17,19
2+3=5
2+5=7
2+7=9
5,7,9 has succesive increase of 2
so only two combination possible 5-7,7-9
after that 11,13,17,......... has not succesive increse of two
so two is the right ans

Is this solution Helpfull? Yes (9) | No (3)  

avinash jha  (9 years ago)

more than 4

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arun  (9 years ago)

(1,1,3,5) is the possible combination
therefore 4!/2! = 12
so more than 4 may be the correct answer

Is this solution Helpfull? Yes | No (18)  

jyothsna  (9 years ago)

more than 4
(2,5,7,11),(3,5,7,11),(5,11,13,17),(7,11,13,17),(11,17,19,23)..... combinations are possible

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prasanthi  (9 years ago)

only 2 combination of prime numbers are enough.....2,3,5,7,11,13,17,19....
2,4,6,8=the difference b/w alternate 2 numbers are 2.....SO
let us take=2+3=5
2+5=7
2+7=9...
the difference is 2...
and next...let us take 4 prime numbers like=2+3+5+7=17
3+5+7+11=26
5+7+11+13=36
so difference is not 2 and difference is not same b/w 2 numbers ...
so answer is 2....i think

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Agniv Chatterjee  (8 years ago)

only 1....


2,3,5,7

2+3=5
2+5=7
2+7=9
....

@ashu 5,7,9 ...bro when did 9 became a prime no ?

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sriraman  (4 years ago)

@ ashu kaushal stupid answer

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