Latest Wipro Aptitude Question SOLUTION: A man driving his bike at 24 kmph reaches his office 5 minutes late. Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time. How far

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A man driving his bike at 24 kmph reaches his office 5 minutes late. Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time. How far is his office?

(1) 24 km
(2) 72 km
(3) 18 km
(4) Data Insufficient

Asked In Wipro (12 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

pratik kumar  (12 years ago)

x/24 - x/30 = 9/60

x = 18km

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Sayantan Dey  (6 years ago)

initial speed 24kmph
+25% speed = 30kmph
speed ratio 24:30 = 4: 5
time 5:4 (as time is inversly propertional to speed)
so 5 - 4 = 1hr = 60 mins late when dist is lcm(24,30)=120 km
(4+5)=9mins late when dist is = (120*90)/60 = 18 km

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Shiv Kumar  (12 years ago)

Answer is 18KM.
D is the distance to office And t is Actual time
driving his bike at 24 kmph reaches his office 5 minutes late.
D=(t+5)*24/60
Had he driven 25% faster on an average he would have reached 4 minutes earlier than the scheduled time means
25% more speed means the new Speed is 30kmph
D=(t-4)*30/60.

Solving these two equations, D comes as 18km.

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karthick  (10 years ago)

Let x km be the distance between his house and office.
While travelling at 24kmph, he would take
x 24 hours.
While travelling at 25% faster speed,
24+25% of 24=24×(
1
4
)=30 kmph, he would take
x
30
hours.

Now as per the problem, time difference = 5 min late + 4 min early = 9 min
⇒
x
24
−
x
30
=9 min
⇒ x= 18 km

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