Latest Wipro Aptitude Question SOLUTION: A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in how man

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(#M40006430) WIPRO Numerical Ability question Time and work problems Keep an EYE

A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in how many days?

Asked In Wipro (12 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

jitendra varshney  (9 years ago)

A+B=10
C=50
lcm of these numbers 50 units
so A+B=5 units/day
C= 1 units/day
------------------
A+B+C=6 units/day...........(i)
given that ,B+C=A
so put this value in equation i
2A=6,
A=3 units/day
now we have
A+B+C=6.........(ii)
A=3,C=1
put these values in equation (ii)
3+B+1=6,
B=2 units/day
and we have 50 units
so time taken by B=50/2=25 days ans.........

Is this solution Helpfull? Yes (13) | No (1)  

nitin kumar  (9 years ago)

A & B can do a piece of work in =10 days
A & B do work in 1 day=1/10
C do a piece of work in =50 days
C do work in 1 day=1/50
also A=B+C-----(1)
now,A+B=1/10
B+C+B=1/10------- (from 1)
2B+C=1/10
2B=1/10-C
2B=1/10-1/50
B=4/(50*2)
B=25 days

Is this solution Helpfull? Yes (7) | No   

sourav maharana  (9 years ago)

A+B=1/10
B-A=-1/50
=>2B=2/25
=>B=1/25
=>B's time=25 days

Is this solution Helpfull? Yes (5) | No   

sbalajisathya  (11 years ago)

6/50(a+b+c)-1/50(a)-3/50(c)

25 days

Is this solution Helpfull? Yes (4) | No (5)  

AMIT KUMAR  (10 years ago)

a can do piece of work = b & c both work together
c alone do work in 50 days

Is this solution Helpfull? Yes | No (9)  

sharvan jain  (9 years ago)

(A +B )'s 1 day work = 1/10

c's 1 day work = 1/50

(A +B +C ) 's 1 day work = ( 1/10 + 1/50) = (3/25)

Since a's 1 day work = (A+B)'s 1day work

so (A+A)' 1day work =3/25

2A =3/25

A = 3/50

B's 1 day work = ( 1/10 - 3/50) = 1/25

Ans. 25 days

Is this solution Helpfull? Yes | No   

komal sharma  (6 years ago)

1/A = 1/B+1/C
1/A+1/B=1/10
1/C=50
BY SOLVING B= 25 days

Is this solution Helpfull? Yes | No   

Nagashayana Reddy  (6 years ago)

A=B+C
A+B=1/10 per day
C=1/50 per day
B=1/10-A
A=1/10-A+1/50
2A=6/50
A=3/50
A+B=1/10
B=1/10-3/50
B=2/50 work done by B per day
so inorder to complete a full work
2/50*x=1
x=50/2
that is 25 days

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umagn  (5 years ago)

LCM Method

A + B = 10 days
C = 50 days

LCM (10,50) = 50

Work of 1 day :
A+B = 50 / 10 = 5 units
C = 50 / 50 = 1 units

work done in 1 day when A,B & C work together :

A+B+C = 5+1 = 6 units

Since work done by A is equal to work done by B & C

therefore,
A = 6 / 2 = 3 units

therefore, B+C = 3

1 day work of C is 1 units

therefore , B's one day work is 2 units

50 / 2 = 25 days

Is this solution Helpfull? Yes | No   

MOKBUL SK  (5 years ago)

A=B+C .......(1)
A+B=1/10 /day ,or, A=1/10 -B, and B=1/50 /day .
from(1), B=A-C
or, B=1/10 -B-1/50
or, 2B=4/50
or, B=2/50 =1/25 /day =25 day

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