Latest Syntel Aptitude Question SOLUTION: Two fill pipes A and B can fill a tank in 30 and 20 hours respectively. Pipe B alone is kept open for half the time and both pipes are kept open for the remaining time. In how many

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(#M40007050) SYNTEL Numerical Ability question pipes and cisterns problem Keep an EYE

Two fill pipes A and B can fill a tank in 30 and 20 hours respectively. Pipe B alone is kept open for half the time and both pipes are kept open for the remaining time. In how many hours the tank will be completely full?
[A] 12 h
[C] 14 h
[B] 13 h
[D] 15 h

Asked In Syntel (12 years ago)

Solved Abha Read Solution (3)

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Read Solution (3) :

Abha  (11 years ago)

Pipe A 1 hr work=1/30
Pipe B 1 hr work=1/20
let total time required to fill the tank =xhrs
since pipe B is open for half hr so work done by pipe B in x/2 hrs =x/40hrs
and work done by pipe (A+B) in remaining x/2 hrs=x/24hrs
so total work done is =x/40+x/24
1=x/40+x/24
=>1=8x/120
=>120=8x
so x=15hrs

Is this solution Helpfull? Yes (16) | No   

suman prasad  (10 years ago)

let x will be completion time

so, x/2*(1/20) + x/2*(1/30 + 1/20)=1
8x=120
x=120/8
x=15 ans

Is this solution Helpfull? Yes (7) | No   

sunkara.koteswararao  (10 years ago)

Easy
a->30 & b->20
take LCM TO BOTH is 60
then a=60/30=2 & b=60/20=3
take time as "x"hrs
is x/2(b)+x/2(a+b)=60
3x/2+5x/2=60 =>8x=120 =>x=15hrs (D)

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