Latest CTS Aptitude Question SOLUTION: A,B,C, can do a work in 8,14,16 days respectively. A does the work for 2 days. B continues from it and finishes till 25% of the remaining work. C finishes the remaining work. How m

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(#M40007196) CTS Numerical Ability question number problem Keep an EYE

A,B,C, can do a work in 8,14,16 days respectively. A does the work for 2 days. B continues from it and finishes till 25% of the remaining work. C finishes the remaining work. How many days would have taken to complete the work?

Asked In CTS (12 years ago)

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Read Solution (4) :

rocky  (10 years ago)

A works for 2 days. since he needs 8 days for completing the whole work he has completed 25% work in 2 days

So remaining work = 75%.

B works till 25% is remaining, i.e. B completes 50 % work which will take him 0.5 * 14 = 7 days.

C completes remaining 25% work which takes him 0.25 * 16 = 4 days.

So total days for work completion = 2 + 7 + 4 = 13 days

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jacky kumar  (8 years ago)

a=1/8*2,b=1/14*7,c=1/16*4
=>2+7+4=13

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Simran  (10 years ago)

Remaining work after A:
= 1 - 2(1/8)
= (4 - 1)/4
= 3/4
No. of days B worked:
1/14x = 1/2
x = 7
No. of days C worked:
x(1/16) = 1/4
x = 4
No. of days:
= 2 + 7 + 4
= 13

Is this solution Helpfull? Yes | No (1)  

niranjan  (8 years ago)

13 days.....................

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