Latest CTS Aptitude Question SOLUTION: Find out the distinct numbers that can be formed by 2, 3, 7, 6 that should be divided by 4?

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(#M40007438) CTS Numerical Ability question Analytical problem Keep an EYE

Find out the distinct numbers that can be formed by 2, 3, 7, 6 that should be divided by 4?

Asked In CTS (12 years ago)

Unsolved Read Solution (8)

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vishal  (10 years ago)

8 is the answer ,vignesh is wrong

Is this solution Helpfull? Yes (6) | No (1)  

Vignesh  (12 years ago)

64 distinct numbers can be formed.
Expln: For a number to be divisible by 4, last two digits must be
divisble by 4.
so 32,36,72,76 are the only for possible combinations at
the last two positions.(i.e., 4 possibilities)
The first position can be filled in 4 ways = 4c1
similarly,second position also can be filled in 4 ways = 4c1.
so totally = (4c1)*(4c1)*4(possible chances)
=4*4*4
=64 chances.

Is this solution Helpfull? Yes (4) | No (8)  

Mani kandan  (9 years ago)

possible number is 8.
numbers are
3276,2376,7632,6732,6372,3672,7236,2736
these r possible number.

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suriya prakash  (8 years ago)

128 is answer.....
last digit is either 2 or 6 divisible by 4..........(4*4*4)*2=128

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Pavithra  (8 years ago)

6732,7632,2736,7236,3672,6372,3672,6372,2376,3276---- 8 numbr !

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Sowmya Ganti  (8 years ago)

8 is the answer.
divisibility by 4 says that the last two digits should be divisible by 4.
hence,32,36,72,76 can the ending digits. and 8 no.s can be formed.

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Aiswarya  (8 years ago)

_ _32,_ _36,_ _72,_ _76 are the possible last two digits there fore 8 ways

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Dipankar Bose  (4 years ago)

_ _ 3 6
_ _ 3 2
_ _ 7 6
_ _ 7 2

2 places left 2 digits left so 2P2
and 2 cases so
2*4=8 ans

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