Latest Infosys Aptitude Question SOLUTION: A train and A Cyclist reaches a station every day at the same time. One day the Cyclist starts 20 minutes late from his house.On his way to station the train crosses him at 5 miles

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(#M40000749) INFOSYS Numerical Ability question Keep an EYE

A train and A Cyclist reaches a station every day at the same time. One day the Cyclist starts 20 minutes late from his house.On his way to station the train crosses him at 5 miles before station.The speed of cyclist is 12mph. Find the speed of the train

Asked In Infosys Yashar (13 years ago)

Unsolved Read Solution (5)

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suchandra raavi  (13 years ago)

In 20 min, the cyclist travels 4 miles. The train crossed him at a distance of 5 miles from station. After the train had reached the station, the cyclist should be 4 miles away (20 min late). So for 1 mile of cyclist, train travels 5 miles. Train is 5 times fast. So ans is 60mph

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Shubhangi  (9 years ago)

The other day cyclist was late by 20 mint.
To cover a dist. of 5miles (@12mph) he need 25 minutes.
At the meantime he meets the train (i.e before 5miles from their actual meeting point)
If he is by time , in another 5mnt (25mnt -20mnt late ) he would have met the train.

It implies that the train is running for 5 minutes (train speed being same)
5miles / 5mnts => 60mph.

Is this solution Helpfull? Yes (2) | No   

kranti  (9 years ago)

could you explain this in a clear manner..So for 1 mile of cyclist, train travels 5 miles. Train is 5 times fast.

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srinivas  (9 years ago)

In 20 min, the cyclist travels 4 miles.
Train crossed him 5 miles from station.

If he starts as usual he and train will meet station.
So, In 20 min train reaches station.
train is 5 miles from station.
so train velocity =5miles/(20 min)
converting into mph it is
15 mph

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chandu  (9 years ago)

Very Nice Problem

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