Latest CTS Aptitude Question SOLUTION: I the numerator o a fraction is increased by 200% and denominator is increased by 250% the resultant fraction is 3/14. What is the original fraction? a)1/2 b)3/4 c)1/4 d)1/8

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(#M40007646) CTS Logical Reasoning question Keep an EYE

I the numerator o a fraction is increased by 200% and denominator is increased by 250% the resultant fraction is 3/14. What is the original fraction?
a)1/2 b)3/4 c)1/4 d)1/8

Asked In CTS F.merlin sheeba (12 years ago)

Solved Rakesh Kumar Kohli Read Solution (5)

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Read Solution (5) :

Rakesh Kumar Kohli  (12 years ago)

Ans. c) 1/4

if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y

3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4

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karthi  (12 years ago)

Answer : c) 1/4

Reason :

Let P and Q be the original numerator and denominator respectively.

P when increased by 200% becomes, P + P(200/100) = P (100 + 200)/100 = 300P/100

Q when increased by 250% becomes, Q + Q(250/100) = Q (100 + 250)/100 = 350Q/100

According to the question, (300P/100) / (350Q/100) = 3/14

Or 300P/350Q = 3/14

Or P/Q = (3/14) x (350/300) = 25/100 = 1/4

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Subhadeep Chowdhury  (10 years ago)

let the original fraction be a/b
according to the given condition,

(1+(200/100))*a 3
---------------- = --
(1+(250/100))*b 14

3a*2 3
---- = --
7b 14

a 1
-- = --
b 4

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bikash ranjan sahoo  (10 years ago)

(3/14)*(350/300)=1/4

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Mani kandan  (10 years ago)

Ans. c) 1/4

if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y
i.e., x+x*200%/y+y*250% =3/14
=>x+x(200/100)/y+y(250/100) =3/14
=>x+2x/y+2.5y =3/14

3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4

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