Latest TCS Aptitude Question SOLUTION: 5. 1! + 2! + ………………. + 50! = ? a) 3.1035 * 10 64 b ) 2. 1021 * 10 65 c) 3.1035 * 10 63 d) 3.1036* 10 62

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5. 1! + 2! + ………………. + 50! = ? a) 3.1035 * 10 64 b ) 2. 1021 * 10 65 c) 3.1035 * 10 63 d) 3.1036* 10 62

Asked In TCS venkatesh (12 years ago)

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Read Solution (4) :

Manish tiwari  (11 years ago)

this summation can be defined by reverse recurssion
if you want the sum of the factorials from 1 to n then start with
s(n) = n
and then
s(i) = i * ( 1 + s(i+1) )
and s(1) gives the summation
for example if n=4 we have
s(4)=4
s(3)=3*(4+1)=15
s(2)=2*(15+1)=32
s(1)=1*(28+1)=33
which agrees with
1!+2!+3!+4! = 1+2+6+24

using a computer program and using this recurssion method I get the sum as
31035053229546199656252032972759319953…

Is this solution Helpfull? Yes (1) | No (1)  

lakshman kumar aditya  (12 years ago)

this que. itself is not clear i guess...>?????

Is this solution Helpfull? Yes | No (5)  

gaurav kumar  (12 years ago)

answer is 3.1035*10^64 ...........i don,t know the exect logic

Is this solution Helpfull? Yes | No (4)  

Amit  (9 years ago)

12624550unit digit will be 3 while none of the options will lead to unit digit 3 so no option will be correctFor 1 unit digit will be 52unit digit will be 13unit digit will be 54unit digit will be 64

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