Latest CADENCE Aptitude Question SOLUTION: Q. A room is 30 X 12 X 12. a spider is ont the middle of the samller wall, 1 feet from the top, and a fly is ont he middle of the opposite wall 1 feet from the bottom. what is the

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(#M40008062) CADENCE question Aptitude Keep an EYE

Q. A room is 30 X 12 X 12. a spider is ont the middle of the samller wall, 1 feet from the top, and a fly is ont he middle of the opposite wall 1 feet from the bottom. what is the min distance reqd for the spider to crawl to the fly.

Asked In CADENCE (12 years ago)

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SARATH  (11 years ago)

h=30; b=12; h=12;

..............
| " |
| |
| | 12
| |
| " |
|..............|
30

Apply Geometry to get the minimum distance.

Mid-point [A] of side wall is at 6.
Spider [B] is at 5 from Mid-point of side wall (or) 11 from bottom (or) 1 form top.
Center point [C] of box is 15 away form the mid-point of side wall.

Then ABC is a right angled triangle.
Sides AB=5; AC=15;
Angle at A=90 degrees
BC=((AB^2)+(AC^2))^1/2
BC=15.811

Similarly,
Mid-point[D] of ooposite sidewall is at 6.
Fly [E] is at 5 from Mid-point of opposite side wall (or) 11 from top (or) 1 form bottom.
Center point [C] of box is 15 away form the mid-point of opposite side wall.

Then DEC is a right angled triangle.
Sides DE=5; DC=15;
Angle at D=90 degrees
CE=((DE^2)+(DC^2))^1/2
CE=15.811

Shortest distance from B(Spider) to E(Fly)
BE = BC + CE
BE = 31.622

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PIYUSH DUBEY  (9 years ago)

very simple geometry, use pythagores theorem
distance b/w them=sq root(30^2+10^2) =31.622

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