Latest Patni Aptitude Question SOLUTION: a man walks at 40kmph and reaches the distance in 10 min less than that of usual . by walking at 60 kmph he reaches 10 minutes earlier. the distance covered by him is.?

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a man walks at 40kmph and reaches the distance in 10 min less than that of usual . by walking at 60 kmph he reaches 10 minutes earlier. the distance covered by him is.?

Asked In Patni (12 years ago)

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asim  (12 years ago)

let x be distance in km ,let t be usual time
given 40km/hr=40/60km/min=2/3km/min 10 min less t+10
given 60km/hr=60/60km/min=1km/min 10 min early t-10
since speed=distance/time
2/3=x/t+10.......eq1
1=x/t-10.....eq2
divide eq 1&2
2/3 = t-10/t+10 => t=50min
x=50-10=40km answer

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rajeev bhai  (8 years ago)

Total distance=x
x/40-x/60=20/60
(3*x-2*x)/120=1/3
x/120=1/3
x=40 km

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