Latest CAT Aptitude Question SOLUTION: When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder is

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(#M40009505) CAT question Keep an EYE

When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder is

Asked In CAT Devendra Marghade (12 years ago)

Solved Pargat Pal Singh Read Solution (2)

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Pargat Pal Singh  (12 years ago)

remainder is 7.

number is 403.
403/9 will give 44 as quotient and 7 as remainder

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Vignesh  (12 years ago)

403 is the smallest three digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7.

403/9 = Remainder : 4

403 is divided by 9, remainder is 4 (399+4)
403 is divided by 7, remainder is 4 (399+4)
403 is divided by 8, remainder is 3 (400+3)
403 is divided by 11, remainder is 7 (396+7)

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