Latest TCS Aptitude Question SOLUTION: A CIRCULAR RADIUS OF DASH BOARD 2.0 FOOT IS AT DISTANCE 20 FEET FROM U .U THROW A DART AT IT. IT HIT THE DASH BOARD AT SOME POINT Q IN A CIRCLE.WHATS THE PROBABILITY THAT Q IS CLOS

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(#M40000956) TCS question DASH BOARD Keep an EYE

A CIRCULAR RADIUS OF DASH BOARD 2.0 FOOT IS AT DISTANCE 20 FEET FROM U .U THROW A DART AT IT. IT HIT THE DASH BOARD AT SOME POINT Q IN A CIRCLE.WHATS THE PROBABILITY THAT Q IS CLOSER TO CENTRE OF CIRCLE THAN THE PERIFERY
1)0.25
2)O.75
3)0.50
4)1.0

Asked In TCS ramprasad (13 years ago)

Solved tk Read Solution (6)

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Read Solution (6) :

suchandra raavi  (13 years ago)

Refer to the 5th diagram in the link:
http://writer.zoho.com/public/suchandra/ques
Now we divide the dart board into two halves. Any point in the inner circle is clearly closer to the center than periphery.since we have divided the circle as r/2 and r/2. The dart can hit at any point in the circle. So total sample space is whole area of the circle = (pi)​(r2)----------eq(1). Now we need to find area of the inner circle. Its (pi)*(r/2)2​= (pi)*​​(r2/4)-----------eq(2)​. Probability is (required event)/(sample space) = ​eq(2)/eq(1) = 1/4=0.25.​

Is this solution Helpfull? Yes (15) | No (2)  

saurabh kolhe  (13 years ago)

for this question no need to make any diagram or make any false solution....
remember the trick given
1.closer to center means 0.25
2.closer to perifery means 0.75
just this is the answer

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tk  (13 years ago)

for the point to be closer to the centre it cshould lie within the area of 1ft radius of the board
so probability=(1^2)/(2^2)=.25

Is this solution Helpfull? Yes (4) | No (7)  

Saptarshi Ghosh  (13 years ago)

AREA OF THE INNER CIRCLE/AREA OF THE OUTER CIRCLE
CONCEPT OF CONCENTRIC CIRCLE IS APPLIED
THEREFORE (PI*R/2)^2/(PI*R)^2
= 1/4
= 0.25

Is this solution Helpfull? Yes (3) | No (3)  

sumangala  (13 years ago)

0.25

Is this solution Helpfull? Yes | No (6)  

chitti  (12 years ago)

((r/2)/r)2=0.25

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