Latest MBA Aptitude Question SOLUTION: The first degit of the square of the two digit number is 8. How many number is satisfied the above condition and how?

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The first degit of the square of the two digit number is 8. How many number is satisfied the above condition and how?

Asked In MBA N.SIVASUBRAMANIAN (12 years ago)

Solved Sneha paliwal Read Solution (5)

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Sneha paliwal  (12 years ago)

ans=29,90,91,92,93,94 .
because 29^2=841
90^2=8100
91^2=8281
92^2=8464
93^2=8649
94^2=8836

Is this solution Helpfull? Yes (9) | No (6)  

Sanjana Patnaik  (12 years ago)

No. Number is satisfied:
Any two digit No. if squared, the unit digit cannot become 8.
For example,
UNIT DIGIT OF
THE TWO DIGIT
NO.(IF) 1 2 3 4 5 6 7 8 9 0
UNIT DIGITS
OF THE SQUARE:1 4 9 6 5 6 9 4 1 0

Is this solution Helpfull? Yes (7) | No (5)  

Vignesh  (12 years ago)

6 two digits numbers are possible.

They are,
29,90,91,92,93,94

29^2=841
90^2=8100
91^2=8281
92^2=8464
93^2=8649
94^2=8836

Is this solution Helpfull? Yes (5) | No (4)  

mamata  (12 years ago)

there are only 5 two digit number who satisfy the given condition. They are 90,91,92,93,94. As it is given that first digit should be 8 means MSB is 8. when we multiply 9 with 9 we get MSB as 8. For two digit is second digit should be less than 5 oterwise MSB increases by 1 becomes 9.

Is this solution Helpfull? Yes (4) | No (1)  

ABHISHEK  (9 years ago)

6.
explaination-
29,90,91,92,93,94

Is this solution Helpfull? Yes (3) | No (2)  

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