Latest Accenture Aptitude Question SOLUTION: Q. If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case.What is the sum of the digits of N ?

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Q. If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case.What is the sum of the digits of N ?

Asked In Accenture Devendra Marghade (12 years ago)

Solved chaitanya Read Solution (6)

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Read Solution (6) :

chaitanya  (12 years ago)

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Is this solution Helpfull? Yes (35) | No (10)  

sumit  (11 years ago)

N = H.C.F. of (4665-1305)=3360, (6905-4665)=2240 and (6905-1305)=5600
we can write it as
3360 = 2*2*2*2*2*3*5*7
2240 = 2*2*2*2*2*2*5*5*7
5600 = 2*2*2*2*2*5*5*7
so, HCF of (3360, 2240 and 5600) = 2*2*2*2*2*5*7 = 1120
Sum of digits of N = ( 1 + 1 + 2 + 0 ) = 4

Is this solution Helpfull? Yes (7) | No   

Vignesh  (12 years ago)

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Let N = H.C.F. of (4665 - 1305),(6905 - 4665) and (6905 - 1305)

=> H.C.F. of 3360, 2240 and 5600 = 1120.

=> Sum of digits in N = [1 + 1 + 2 + 0 = 4]

Is this solution Helpfull? Yes (3) | No (8)  

anil kumar  (11 years ago)

for this we have to find the H.C.F of numbers:
so,H.C.F of 1305 and 4665 is 65 and so on complete will be 1120
then sum of digit is:4

Is this solution Helpfull? Yes (3) | No (6)  

AMIT KUMAR  (10 years ago)

4665-1305=3360
6905-1305=5600
6905-4665=2240
HCF of 2240,3360,5600=1120
2240)3360(1
2240
----
1120)2240(2
2240
----
0000
1120)5600(5
5600
----
0000
HCF=1120
ans=1+1+2+0
=4
second method of finding HCF
2240=2*2*2*2*2*2*5*7
3360=2*2*2*2*2*3*5*7
560=2*2*2*2*2*5*5*7
HCF=2*2*2*2*25*7
=1120
so sum of digit of N=1+1+2+0=4

Is this solution Helpfull? Yes (2) | No (1)  

Pallavi Savant  (9 years ago)

4665-1305=3360
6905-4665=2240
now: 3360-2240=1120
1+1+2+0=4

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