Latest TCS Aptitude Question SOLUTION: A bag contains 5 green and 7 blue balls.another one contains 4 green and 8 blue balls.if a bag is choosen randomly and a ball is drawn from it at random,then find the probability t

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A bag contains 5 green and 7 blue balls.another one contains 4 green and 8 blue balls.if a bag is choosen randomly and a ball is drawn from it at random,then find the probability that it is green:
(A)3/4 (B)1/4 (C)5/8 (D)3/8 (E)none of these

Asked In TCS Ragini (13 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

avik mukherjee  (13 years ago)

(1/2*5/12)+(1/2*4/12)=3/8

Is this solution Helpfull? Yes (9) | No (2)  

KALPANA G  (13 years ago)

probability of choose a first bag=1/2,
probability of draw a green ball from first bag=5/12,
Now, probability of get green ball from first bag randomly=1/2 * 5/12=5/24.
similarly, for second bag = 1/2 * 4/12=1/6.
Therefore, total probability = 5/24 + 1/6 =3/8(d)

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AMITABH BARMAN  (13 years ago)

sorry my mistake it would be 9/24=3/8

Is this solution Helpfull? Yes (3) | No   

Gaurav Chakraborty  (13 years ago)

AMITABH BARMAN check ur solution.....it will be 3/8.

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Krishna KAnt Tiwari  (13 years ago)

1/2(5/12+4/12)=9/24=3/8
ans=3/8

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AMITABH BARMAN  (13 years ago)

probability that the ball is green will be first picking a ball form a bag whose probability itself is half and then picking up green ball from it and then same for the next bag
probability of ball being green=1/2 x 5/12 + 1/2 x 4/12 =9/12=3/4 so then the answer is a

Is this solution Helpfull? Yes (1) | No (7)  

Amrit  (13 years ago)

D

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kshiti patel  (6 years ago)

probability for a bag to be choosen = 1/2
for first bag probability of green ball = 5/12
for another bag probability of green ball = 4/12
so , probability = (1/2*5/12)+(1/2*4/12) = 3/8

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