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(#M40013850) TCS MATHS PUZZLE Keep an EYE

if 31x+29y+30z=366 then what is the value of x+y+z?

a)11 b)12 c)13 d)14

Asked In TCS Submited By-- sobhan dutta (3 Month ago)

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(#M40013845) TCS MATHS PUZZLE Keep an EYE

the no when divisible by 5,8 gives reminders 3,1 resp.

Asked In tcs Submited By-- sasi (3 Month ago)

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(#M40013844) TCS MATHS PUZZLE tyres Keep an EYE

if 8 tyres were used on a bus (6 tyres ) which has traveled 16000 km , how many km did each tyre sustain .if all the tyres were used equally in sustaining this distance

Asked In tcs Submited By-- rishi (3 Month ago)

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(#M40013835) TCS MATHS PUZZLE calender Keep an EYE

The last day of a century cannot be?

Asked In tcs Submited By-- satya sree (3 Month ago)

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(#M40013831) TCS MATHS PUZZLE Keep an EYE

Consider the graph G0 with 3 components which are triangles. G0 has 9 vertices labeled
A to I and 9 edges (A, B), (B, C) … as shown below.
If each vertex of G0 is assigned a red or a green color, then we say that an edge is
colored if its ends have different colors.
Ajai and Rekha color the vertices of G0 in the following manner. Ajai proposes a color
(red or green) and Rekha chooses the vertex to apply this color. After 9 turns, all the
vertices of G0 are colored and the number of colored edges is counted.
Suppose Ajai would like to maximize the number of colored edges while Rekha would
like to minimize the number of colored edges. Assuming optimal play from both players,
how many edges will be colored? Explain ur reasoning.

Asked In Tcs Submited By-- gauthami (3 Month ago)

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(#M40013825) TCS MATHS PUZZLE Keep an EYE

there are 7 verticle and 9 horizontal line....find total number of square and rectangle which can be made by these lines

Asked In tcs Submited By-- abhishek mishra (3 Month ago)

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(#M40013820) TCS MATHS PUZZLE perfect square Keep an EYE

for which of the following n is the numeber 2^74 + 2^2058 + 2^2n a perfect square

A.2010
B.2011
C.2012
D.2100

Asked In TCS Submited By-- loganand (4 Month ago)

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(#M40013819) TCS MATHS PUZZLE Percentage Keep an EYE

If A is 30% of X. X is 20% of Y. B is 50% of Y. then A/B =

i) 4/3
ii) 3/25
iii) 6/5
iv) 3/250

Asked In TCS Submited By-- loganand (4 Month ago)

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(#M40013818) TCS MATHS PUZZLE correct addition Keep an EYE

641+852+973=2456 is not correct. what is the largest digit that can changed to make the correct addition

A.4
B.5
C.6
D.7

Asked In TCS Submited By-- loganand (4 Month ago)

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(#M40013817) TCS MATHS PUZZLE correct addition Keep an EYE

The addition 641+852+973=2456 is incorrect. What is the largest digit that can be changed to make addition correct

A.4
B.5
C.6
D.7

Asked In TCS Submited By-- loganand (4 Month ago)

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(#M40013799) TCS MATHS PUZZLE Keep an EYE

A spaceship on an inter-galactic tour has to transfer some cargo from a base camp to
a station 100 light sec away through an asteroid belt. The ship can carry a maximum of
100 kgs of cargo and, as a result of colliding against the asteroids, every 2 light sec of
travel causes it to lose 1 kg of cargo. There are 300 kgs of cargo available at the base
camp. Find the maximum amount of cargo (in kg) that the ship can transfer to the
station? Assume that the spaceship can store the cargo at any intermediate point along
the way and that stored cargo is not depleted by the asteroids.

Asked In tcs Submited By-- gauthami (4 Month ago)

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(#M40013714) TCS MATHS PUZZLE Phase I Keep an EYE

1. Alok and Bhanu play the following game on arithmetic expressions. Given the
expression
N = (Θ + A)/B + (Θ + C + D)/E
where A, B, C, D and E are variables representing digits (0 to 9), Alok would like to
maximize N while Bhanu would like to minimize it. Towards this end, they take turns in
instantiating the variables. Alok starts and, at each move, proposes a value (digit 0-9)
and Bhanu substitutes the value for a variable of her choice. Assuming both play to their
optimal strategies, what is the value of N at the end of the game? Also find a sequence
of moves (digits by Alok and variables by Bhanu) that would yield this value.
Note: Moves that lead to a divide-by-zero condition are disallowed. A non-optimal
sequence of moves is (5 → B, 6 → C , 3 → D, 2 → E, 0 → A) and the expression
evaluates to Θ/5 + (Θ+9)/2.
2. The mean, unique mode, median and range of 21 positive integers is 21. What is the
largest value that can be in this sequence? Also find such a sequence.
Note: Given a sequence of numbers a(1) ≤ a(2) ≤ ... ≤ a(n),
 The median of the sequence is the middlemost value in the sequence if n is
odd and the average of the two middle values if n is even.
 The mode is the most occurring value in the sequence
 The range is the difference between the largest and the smallest values, i.e.
a(n) - a(1).
For example, the sequence 2, 3, 4, 6, 6, 9 has mean = (2 + 3 + 4 + 6 + 6 + 9)/6 = 5,
median = (4+6)/2 =5, mode = 6, and range = 9 – 2 = 7.

Asked In TCS Submited By-- Som (4 Month ago)

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(#M40013705) TCS MATHS PUZZLE Keep an EYE

P(x)= x^2012+x^2011+x^2010+...+x+1)^2 - x^2012 Q(x)=x^2011+x^2010+..+x+1 The remainder when P(x) is divided by Q(x) is ?

Asked In TCS Submited By-- M.R.kartheek (4 Month ago)

Puzzle Status: Solved     By »» Atul Read Solution (6)

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(#M40013628) TCS MATHS PUZZLE Keep an EYE

Cubes c1,c2,c3.....and Spheres s1,s2,s3,....are defined in the following way.
-s1 has radius 4cm.
-For each n>0, Cn is inscribed in Sn and Sn+1 is inscribed in Cn(ie c1 is inscribed in s1,s2 is inscribed in c1,c2 is inscribed in s2 and so on)
Let Vn be the sum of the volumes of the first n cubes c1,c2,c3....Cn.Then as n->infinity Vn approaches.

options i)384(1+3root3)/13 2)64(1+3root3)/13 3) 128(1+3root3)/13 4) infinity , ie Vn is unbounded.

Asked In tcs Submited By-- UN (5 Month ago)

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(#M40013627) TCS MATHS PUZZLE Keep an EYE

the maximum possible value of (6^x-36^x) over all real values of x is
options 1) infinity 2)0 3)1 4)1/4 5) 1/2

Asked In tcs Submited By-- machanurus suresh (5 Month ago)

Puzzle Status: Solved     By »» Karan Read Solution (6)

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(#M40013626) TCS MATHS PUZZLE Keep an EYE

3.2-(5-33[4/2+1]) =
a)-21 b)32 c)45 d)60 e) 78

Asked In tcs Submited By-- naresh (5 Month ago)

Puzzle Status: Solved     By »» Karan Read Solution (5)

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(#M40013624) TCS MATHS PUZZLE Keep an EYE

2-(5-33[4/2+1])=

Asked In tcs Submited By-- naresh (5 Month ago)

Puzzle Status: Solved     By »» Garima Read Solution (10)

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(#M40013623) TCS MATHS PUZZLE Keep an EYE

The length of a rectangle is 25 m more than its breadth. If its length is decreased by 15 m and its breadth is increased by 10 m, it would become a square. Find its perimeter (in m).
a)70 b) 30 c) 190 d) None of the Above

Asked In tcs Submited By-- naresh (5 Month ago)

Puzzle Status: Solved     By »» Smita Read Solution (3)

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(#M40013622) TCS MATHS PUZZLE Keep an EYE

. A and B are standing in a queue. A is 18th from the front and B is 11th from the back. If there are 5 persons standing between A and B, then how many persons are standing in the queue?
a)34 b) 22 c) 28 d) Cannot be determined

Asked In tcs Submited By-- naresh (5 Month ago)

Puzzle Status: Solved     By »» Polisetty Pavan Kumar Read Solution (9)

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(#M40013621) TCS MATHS PUZZLE Keep an EYE

In the square above, 12w = 3x = 4y. What fractional part of the square is shaded?
a)2/3 b) 14/25 c) 5/9 d) 11/25 e) 3/7

Asked In tcs Submited By-- naresh (5 Month ago)

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