Latest TCS Aptitude Question SOLUTION: If a number 272758 and 273437 is divided by N then they give remainder as 13 and 17 respectively. find the sum of digits of number N.

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If a number 272758 and 273437 is divided by N then they give remainder as 13 and 17 respectively. find the sum of digits of number N.

Asked In TCS pramay patidar (11 years ago)

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ramya keerthana  (11 years ago)

since 13 n 17 are remainders
thus subtracting gives 272758-13=272745 n 273437-17=273420
then GCF of 272745,273420 gives 45
ANS:4+5=9 (easy to find gcf,N may be less than 45 also,GO ACCORDING TO THE OPTIONS)

Is this solution Helpfull? Yes (42) | No (2)  

Rajat Dadhich  (11 years ago)

find HCF of
272758-13 and 273437-17,,,
HCF will be 45
Hence, 4+5,,,
ans is 9

Is this solution Helpfull? Yes (10) | No (1)  

SAKSHI MISRA  (11 years ago)

hey frnz..ye ques mere aptitude me aya hai ques repeat ho rey hai believ me i cleared the apt..

Is this solution Helpfull? Yes (6) | No (3)  

AVINASH MODI  (11 years ago)

ANSWER should be 1+5 = 6 .
because given data is 13 and 17 as remainder so minus both of no. from 272758-13=272745 and 273437-17=273420 so now suppose x,y are answer and diviser is N for both no.
272745/n=x----(1)
273420/n=y---(2)
compare both equations.
and x/y=18183/18228
so now these two are values of no when it divided by same no N .
for find value of N is 272745/273420 is divide by 18183 and 18228 so no will be N=15 so sum of digit is N=1+5
N=6

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gautam kumar sharma  (11 years ago)

hey sakshi congrats
ans to bta do

Is this solution Helpfull? Yes (5) | No (1)  

Ravi Bhole  (11 years ago)

Here it is not unique solution
272758 -13 = 272745 and 273437- 17 =272720
272745 and 272720 are divisible by 1,3,9,5,15,45
So Sum of the digits is 1 or 3 or 5 or 9 or 6. (4+5 =9)
N is not unique. It is not mentioned greatest 2 digit number.
272720 is divisible by 4 and 7 but 272745 is not divisible by 4 and 7 it is divisible by 11. Here I have considered all factors

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vikrant  (11 years ago)

its sure that answer has to be bigger than 17 as we getting it as remainder
other wise if ans is like 9 ,6 etc then why don't they go for more simplification
17mod9=8
13 mod 9=4

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Dhirendra Yadav  (7 years ago)

272758-13=272745
273437-17=273420
now calculate hcf of 272745 & 273420 which will be 15
sum of digits will be 1+5=6.

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