Latest TCS Aptitude Question SOLUTION: In how many ways can 2310 can be expressed as product of 3 factors??

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In how many ways can 2310 can be expressed as product of 3 factors??

Asked In TCS TAUSEEF AMEEN (8 years ago)

Unsolved Read Solution (10)

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Manikanta  (8 years ago)

factors=2*3*5*7*11
a+b+c=1====> [1+3-1]C(3-1)=3
so ans is 3*3*3*3*3=243

Is this solution Helpfull? Yes (8) | No (1)  

Mohana Sengupta  (8 years ago)

factors of 2310=2x3x5x7x11. number of factors is the sum of the powers +1... so, number of factors is 2^5=32. so there are 32/3=10 ways in which we can represent the number as a product of 3 factors

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sumit kumar  (8 years ago)

The prime factore of 2310 is 2^1*3^1*5^1*7^1*11^1..there is a direct formula (3^n-1 +1)/2 here n is no of distinct prime no.
So here n=5 so answer is 41..if u want explanation then i can provide u.

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balram sharma  (8 years ago)

@SUMIT KUMAR please give the explanation for (3^n-1 +1)/2

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sumit kumar  (8 years ago)

@BALRAM SHARMA you can solve it another way also..
prime factor of 2310 is 2^1*3^1*5^1*7^1*11^1.
we have to make product of three factor then think as
we fix 1 _ _ 16 ways(by rule of factor in product of two)
2 _ _ 8-1=7(because one product will also present above)
3 _ _ 8-2=6
4 _ _8-3=5
7 _ _8-4=4
11 _ _8-5=3
add all we get 41.

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surya teja  (8 years ago)

ans is 15

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chidige jhansi  (8 years ago)

Ans is 9

Is this solution Helpfull? Yes | No (2)  

Vidyanand Yadav  (8 years ago)

2310=2x3x5x7x11 (all prime)
Total no of factors should be 3, so we have to select 3 nos. from 5 and combine them together. Rest 2 will be the other factors. And we can select 3 nos. from 5 in 5C3 i.e. 10 ways.
So answer will be 10 ways.

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SHUBHRANSHU  (8 years ago)

(5C3)+ (5C2*3C2)=40

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NARENDRA KUMAR  (8 years ago)

Hii guys,
Plz explain me answer. how to get answer

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