Latest Elitmus Aptitude Question SOLUTION: in a triangle ABC angle a is the smallest one. A+7B=112 find the range of value c

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(#M40018117) ELITMUS Numerical Ability question Keep an EYE

in a triangle ABC angle a is the smallest one. A+7B=112 find the range of value c

Asked In Elitmus akshay kesharwani (11 years ago)

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Satyaranjan  (11 years ago)

A+7B=112
=>7B=112-A:So it means 112-A should be divisible by 7 and the values of A that satisfies this condition are 0,7,14......
So 1st take A as 7,then B=(112-7)/7=15,C=180-(7+15)=158
then take A as 14,then B=14 and C=180-28=152
Here A=B,it does not satisfy the condition that A is the smallest one.So the answer would be A=7,B=15,C=158.

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Karan  (11 years ago)

When A=0 ( approx), B= 16 deg (approx); C= 164 deg
when A=Approx B= approx14; A+B=28 deg (approx); C= 180-28=152 deg

so range of C is (152,164)

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Rohit  (11 years ago)

@ Satyaranjan,

There is no condition that Angles should be integer only.
A can have values from 0.00000000001 to 13.999999999999
and accordingly C will be in range of 152.00000000001 to 163.999999999999
or (152,164) as explained by Karan.
Have fun.

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Shalu Jain  (11 years ago)

A+7B=112
it is clear that A=14, then it becomes A>=B, but A is smallest angle)
so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)
finally we can say
0.0001

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Narendra  (11 years ago)

A+7B=112
neglect A(Bcoz a is small)
7B=112 => B=16
In /_ABC total degrees 180...
So,
C angle in range 16

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