Latest Elitmus Aptitude Question SOLUTION: what is the value of log(e(e(e..)^1/2)^1/2)^1/2? option a) 0 b) 1 c) 1/2 d) 1/3

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(#M40028849) ELITMUS question Quant Keep an EYE

what is the value of log(e(e(e..)^1/2)^1/2)^1/2?
option
a) 0
b) 1
c) 1/2
d) 1/3

Asked In Elitmus rahul (10 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Gourav Rusiya  (10 years ago)

Question was to find.......log(e(e(e...)^1/3)^1/3)^1/3 = ??
Sol: Let y=log(e(e(e...)^1/3)^1/3)^1/3
y=1/3 log e.(e(e..)^1/3)^1/3
3y=log e + log(e(e(e...)^1/3)^1/3)^1/3
3y= 1 + y
2y = 1
y = 1/2......answer......was easy naaaaa

Is this solution Helpfull? Yes (28) | No   

subhajit mondal  (10 years ago)

ans is a)o

Is this solution Helpfull? Yes (4) | No (1)  

vinay kumar jain  (10 years ago)

right answer is 1.

Is this solution Helpfull? Yes (2) | No   

Akshay Kumar Singh  (10 years ago)

you write a wrong question my frd..
ques is..log(e(e(e...)^1/3)^1/3)^1/3..
so thw write answer is..1/2

Is this solution Helpfull? Yes (1) | No (2)  

Rahul Yadav  (10 years ago)

@subhajit, saurabh, akshay : Approach plz

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saurabh prakash  (10 years ago)

b> 1 sure...

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pankaj kumar  (10 years ago)

if the base is e then ans is :1
and if base is 10 then ans is:0

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