Latest TCS Aptitude Question SOLUTION: 1223334444112222333333444........... 2001 term in sequence????

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(#M40030787) TCS Logical Reasoning question Keep an EYE

1223334444112222333333444........... 2001 term in sequence????

Asked In TCS surendra raju (10 years ago)

Unsolved Read Solution (11)

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RAKESH  (10 years ago)

1223334444=10 terms
11222233333344444444=20 terms
Sn=10+20+30+....+10*n=10(1+2+3+...+n)
if n=19,Sn=10*19*20/2=1900
if n=20,Sn=10*20*21/2=2100
so after 1900 there will be 111...(20times)222...(40times)333...(60times)
so 2001th term is 3
ans 3

Is this solution Helpfull? Yes (48) | No (3)  

VALLURU VENKATA KIRAN KUMAR  (10 years ago)

1223334444-10TERMS
11222233333344444444-20 TERMS2
1111222222223333333333334444444444444444-30 TERMS
......
NUMBER OF TERMS =10[1+2+3..........]
THIS SUM SHOULD BE LESS THAN 2001
10*[n(n+1)/2]

Is this solution Helpfull? Yes (5) | No   

Nikunj  (10 years ago)

1223334444=10 terms
11222233333344444444=20 terms
Sn=10+20+30+....+10*n=10(1+2+3+...+n)
if n=19,Sn=10*19*20/2=1900
if n=20,Sn=10*20*21/2=2100
so after 1900 there will be 111...(20times)222...(40times)333...(60times)
so 2001th term is 3
ans 3

Is this solution Helpfull? Yes (4) | No (3)  

samadi durga prasad  (10 years ago)

1223334444=10 terms
11222233333344444444=20 terms
111222222333333333444444444444=30 terms
then
so given series can be written as (10 20 30 40 ...........)=>10(1 2 3 4 ......)
now we have to find 2001 term
1 2 3 4 are natural numbers
10*[n(n+1)/2]

Is this solution Helpfull? Yes (2) | No (1)  

aravind  (10 years ago)

here the sequence is like 10,20,30,40..... terms
by using the formula 10*n(n+1)/2 let here n=20 then no.of terms in that sequence is 2100 i.e., 21-1's and 42-2's and 63 -3's and 84-4's if we subtract 2100-84=2016 but here 3's lie b/n (1974,2016) there by we can easily say that 2001 term in sequence is 3

Is this solution Helpfull? Yes (2) | No (2)  

Devi Nallamilli  (10 years ago)

2001 term is 2
1223334444=10 terms
11222233333344444444=20 terms
1111222222223333333333334444444444444444-40 TERMS
so each time it doubles
10
20
40
80
160
320
640
1280
2560
it exceeded
number of 1's in
1 in 10
2 in 20
4 in 40
256 in 2560
so 1280+256 = 1536
number 2's are double than the 1's
512 2's in 2560
so 1536+512 = 2048
so finally 2001 term is 2

Is this solution Helpfull? Yes (2) | No (6)  

Ankit  (10 years ago)

answer is 4

Is this solution Helpfull? Yes (1) | No   

vikas  (9 years ago)

1 22 333 4444 (10 terms)
11 2222 333333 44444444 (20 terms)....subsequently 30 terms,40,50....so on.
now

these no. of terms add up to 2000 after 20 such sets exactly. (Sn formula)

therefore 2001 the term will be starting of another new set starting with 1

ans. 1

Is this solution Helpfull? Yes (1) | No   

likhitha  (9 years ago)

can any one explain why after 1900 there will be 111...(20times)...
plz.....can any one answer...

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ekta khatri  (9 years ago)

i think d answer shud be 3.....

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R.Hima Bindu  (9 years ago)

after 1900, there will be 20times 1 bcz, from the series given,
after 10 times 1 is multipled by 2, no of terms series will be 10,20,40,80,160,320,640,1280,2560, so for 2001th term 10*2
so 1=10*2=20,2=2*10*2=40,3=3*10*2=60

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