Latest TCS Aptitude Question SOLUTION: Odd one out 5,15,30,135,405,1215,3645

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(#M40039802) TCS Numerical Ability question Keep an EYE

Odd one out
5,15,30,135,405,1215,3645

Asked In TCS payel (9 years ago)

Unsolved Read Solution (22)

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Narasapu Hari prasad  (9 years ago)

Ans is 30(3 rd term)
first term 5
second term 5*3=15
third term 15*3=45 so there should be 45 instead of 30
fourth term 45*3=135
fifth term 135*3=405
sixth term 405*3=1215
sevnth term 1215*3=3645
so odd one is 30, there should be 45 instead of 30.

Is this solution Helpfull? Yes (32) | No   

shekhar singh  (9 years ago)

answer can be either 5 or 30

5 coz it is only prime no in the series

30 coz it is only even no in the series

Is this solution Helpfull? Yes (4) | No   

BHASKAR MANDAL  (9 years ago)

there are two possibilities,

(i) all are the number is multiplied by 3 to get the next number
i,e 5*3 =15
15*3 = 45 but its 30
45 * 3 = 135
and so on
so the odd number will be 30

possibility (ii)

all are divisible by 3 except 5
so the odd number will be 5

the answer depends on the option

Is this solution Helpfull? Yes (2) | No   

rachakonda renuka  (9 years ago)

30
every digit is mutiple of 3
5*3=15
15*3=45
.
.
.

Is this solution Helpfull? Yes (1) | No   

gaurav singh  (9 years ago)

answer=5
sum of digits of each number is divisible by 3
1+5=6
3+0=3
1+3+5=9
4+0+5=9
1+2+1+5=9
3+6+4+5=18

Is this solution Helpfull? Yes (1) | No   

sasikumar  (9 years ago)

answer is 135.
5 * 3^0=5
5 * 3^1=15
5 * 3^2=45
5 * 3^3=135....and so on .

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KAZI AMINUDDIN ZAMAN  (9 years ago)

30 since only even number in series. Plus does not follow 15-3= 45

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PRANAVI MANCHIRAJU  (9 years ago)

I THINK ANSWER IS 30 SINCE SERIES GOES LIKE THIS
5*3=15
15*3=45
45*3=135
135*3=405
AND SO ON.................

Is this solution Helpfull? Yes (1) | No   

ROSHAN SINGH  (7 years ago)

30 should not be there as each new no is coming by multiplying the previous one with 3.
so 5*3=15
15*3=45
45*3=135
135*3=405
405*3=1205
1205*3=3645

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Dhamayanthi.s  (9 years ago)

5 is not divisibility of 3

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Anurag patel  (9 years ago)

5*3=15,15*3=45,45*3=135,135*3=405,405*3=1215,1215*3=3645

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valli  (9 years ago)

30 since all the numbers in the series are ending with 5 and 30 alone end with 0

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Soumyadip Hazra  (9 years ago)

Ans-30
x*3

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VIVEKANAND NAGAR  (9 years ago)

ans. 30 Because each term is multiplied by 3 with his previous values so the result will be 30 .

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Ashok Kumar  (9 years ago)

30 is the odd man

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Theodar  (9 years ago)

5*3=15
15*3=45(but is given as 30)
135*3=405
405*3=1215
1215*3=3645
So th odd one out is---->30

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Ravi Nirban  (9 years ago)

30
every digit is multiple of 3
5*3=15
15*3=45
.
.
.

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TANMOY DEY  (9 years ago)

all r divisible by 3 except 5.. so ans is 5

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Riju Ghosh  (9 years ago)

ans = 30, it should be 45
explanation…
5x3=15
15x3=45
45x3=135
135x3=405
405x3=1215
1215x3=3645

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Ayush Upadhyaya  (9 years ago)

Anwer is 5 because except 5 all are multiples of 15
15*1=1
15*2=30
15*9=135
15*27=405
15*81=1215
15*243=3645

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durga  (7 years ago)

30.all of them are ends with 5 except 30

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sachin soni  (7 years ago)

The odd one out is 30
because each term in the series is equal to 3 times the previous term
therefore 15*3 = 45 should be there in place of 30.

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