Latest general Aptitude Question SOLUTION: The sum of the areas of two squares is 640 meter sq. If the difference in their perimeters be 64 m,find the sides of the two squares

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(#M40009594) GENERAL question Keep an EYE

The sum of the areas of two squares is 640 meter sq. If the difference in their perimeters be 64 m,find the sides of the two squares

Asked In general Devendra Marghade (12 years ago)

Solved Rakesh Kumar Kohli Read Solution (1)

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Rakesh Kumar Kohli  (12 years ago)

The sides of two squares is 24 meters and 8 meters.
area of square of 24 meters side = 576 sq. meter
area of square of 8 meters side = 64 sq. meter
The sum of the areas of two squares is = 576 + 64 = 640 meter sq
the difference in their perimeters = 96 - 32 = 64 meters

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