M4maths Previous Puzzles

18 Apr 2014 Coded language

If in coded language
MAMTA = 8
SAUMYA = 80
MONIKA = 35
then
RASHMI = ?

OPtion

1) 16
2) 26
3) 42
4) 38
5) 14
6) 81
7) 39
8) 14
9) 27
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
MAMTA = (13)(1)(13)(20)(1) = 28-20 = 8 (Sum of Odd no - Sum of Even no)
SAUMYA = (19)(1)(21)(13)(25)(1) = 80-0 = 80
MONIKA = (13)(15)(14)(9)(11)(1) = 49-14 = 35
Similarly
RASHMI = (18)(1)(19)(8)(13)(9) = 42-26 = 16
Option 1)

Correct Option: 1 Best Solution (18)

Dr.Dipin Singh   10 years AGO

R-18
A-1
S-19
H-8
M-13
I-9

Sum of nos. Having odd values = 1+ 19 + 13 + 9=42
Sum of nos. Having even values = 18+8= 26
Their difference = 42-26= 16

Like? Yes (17) | No (7)  

llamar   10 years AGO

assign values to alphabets as follows
a=1,b=2......................z=26
MAMTA = 8
l.h.s=13,1,13,20,1(mamta)
=sum of odd values-sum of even values
=(13+1+13+1)-20
=28-20=8
like wise SAUMYA=19+1+21+13+25+1=80
MONIKA =(13+15+9+11+1)-14=35
RASHMI = (1+19+13+9)-(18+8)=16

Like? Yes (1) | No   

Karan   10 years AGO

RASHMI.... 18 1 19 8 13 9
(1+19+13+9)-(18+8)= 16

Like? Yes (6) | No (6)  

azharshahid01@gmail.com   10 years AGO

Subtract even from odd.
MAMTA = 13,1,13,20,1=> (13+1+13+1)-20= 8
SAUMYA= 19,1,21,13,25,1=> 80
MONIKA= 13,15,14,9,11,1=> (13+15+9+11+1)-14= 35
Similarly,
RASHMI= 18,1,19,8,13,9=>(1+19+13+9)-(18+8)=16
So, answer is 16.

Like? Yes (7) | No (9)  

Ann Theressa   10 years AGO

Put A=1,B=2...Z=26

ans = sum of odd numbers - sum of even numbers

MAMTA
(13+1+13+1)-20 = 8

SAUMYA
(19+1+21+13+25+1)-0 = 80

MONIKA
(13+15+9+11+1)-14 = 35

RASHMI
(1+19+13+9)-(18+8) = 16

Like? Yes (5) | No (8)  

B. SIREESHA   10 years AGO

a=1,b=2,....
MAMTA=13+1+13-20+1=8
SAUMYA=19+1+21+13+25+1=80
MONIKA=13+15-14+9+11+1=35
(difference between sum of all even nos and sum of all odd nos)
RASHMI=-18+1+19-8+13+9= 42-26=16

Like? Yes (3) | No (6)  

MD SOHAIL AKHTER   10 years AGO

A=1, B=2,C=3,....Z=26
Add all the even no. and odd no., then subtract the even no. from odd no.
MAMTA=(13+1+13+1)-20=8

similarly
RASHMI=(1+19+13+9)-(18+8)=16

Like? Yes (3) | No (7)  

ANUP KUMAR   10 years AGO

M(13),A(1),M(13),T(20),A(1)
(sum of odd no.)-(sum of even no.)
(13+1+13+1)-(20)=8 =MAMTA
S(19),A(1),U(21),M(13),Y(25),A(1)
(19+1+21+13+25+1)-(0)=80 =SAUMYA
M(13),O(15),N(14),I(9),K(11),A(1)
(13+15+9+11+1)-(14) = 35 =MONIKA
THEN
R(18),A(1),S(19),H(8),M(13),I(9)
(1+19+13+9)-(18+8)=16 = RASHMI

Like? Yes (2) | No (6)  

Varunraj Reddy   10 years AGO

Given MAMTA=8
(Sum of odd num characters)-(sum of even num characters)=(13+1+13+1)-(20)=8
Similarly
RASHMI=(1+19+13+9)-(18+8)=42-26=16

Like? Yes (2) | No (6)  

shree   10 years AGO

remain- 16

Like? Yes (2) | No (6)  

Naveen Kumar   10 years AGO

(sum of odd no. encountered)-(sum of
even no. encountered)

Like? Yes (3) | No (7)  

sruthi   10 years AGO

for M A M T A - add odd values and subtrat it from even number
13+1+13+1=28
28-20=8

for R A S H M I
1+19+13+9=42
42-18+8=16
16 IS THE ANSWER

Like? Yes (2) | No (6)  

Vinay Sipani    10 years AGO

Add all alphabets of odd number and subtract alphabets of even number.

MAMTA=> M+A+M-T+A = 8
MONIKA=> M+O-N+I+K+A = 35
RASHMI=> -R+A+S-H+M+I = 16

Like? Yes (1) | No (5)  

DILEEP KUMAR   10 years AGO

Let A=1,B=2,....Z=26 then
EXAMPLE:
M A M T A = 13 1 13 20 1
THEN FIND DIFFERENCE BETWEEN SUM OF ODD VALUE AND SUM OF EVEN VALUES
EX:
(13+13+1+1)-(20)=8
LIKE WISE
RASHMI= 18,1,19,8,13,9
ANS=(1+19+13+9)-(18+8) = 16

Like? Yes (1) | No (5)  

Santosh Vishwakarma   10 years AGO

ANS =(sum of odd positons-sum of even postons)

NOTE: Take A=1,B=2,........Z=26.

Like? Yes (1) | No (5)  

Surya Narayana K   10 years AGO

Coding as follows..

Result will be
(sum of the odd numbered alphabets) -(sum of the even numbered alphabets).

MAMTA=(13+1+13+1)-20=8
SAUMYA=19+1+21+13+25=80.
MONIKA=13+15-14+9+11+1=35
Similarly
RASHMI=-18+1+19-8+13+9=16

So ans is 16(Option 1)

Like? Yes (1) | No (5)  

Panchanand   10 years AGO

MAMTA 13 1 13 20 1 =(13+1+13+1-20= 8) (SUM OF ODD NUMBERS - SUM OF EVEN NUMBERS)
SAUMYA 19 1 21 13 25 1 = (19+1+21+13+25+1 = 80)
MONIKA 13 15 14 9 11 1 = (13+15+9+11+1-14 = 35)
RASHMI 18 1 19 8 13 9 = (1+19+13+9-18-8 = 16)

Like? Yes (1) | No (5)  

SHUBHAM KUMAR   10 years AGO

mamta=13+1+13+20+1=28-20=8
saumya=19+1+21+13+25+1=80-0=80
monika=13+15+14+9+11+1=49-14=35
rashmi=18+1+19+8+13+9=42-26=16

Like? Yes (2) | No (6)