A cistern can be filled by pipes A and B in 4 hours and 6 hours respectively. When full, the tank ca

Amit Toor   9 years AGO

When all Taps are Open Water will be filled with rate= 1/4 + 1/6 - 1/8 = 7/24 per hour
Time taken =1/rate
we get 24/7 hour which is 3 hours 25.71 Minutes close to 7th option

Like? Yes (6) | No   

sumit   9 years AGO

in 1 hr 1/4+1/6-1/8=7/24 part of tank will be filled
so time taken to fill the full tank will be 1/(7/24)=24/7hrs
=3hrs 26 minute
option(7)

Like? Yes (4) | No (1)  

sompon temtheerakij   9 years AGO

rate of A = 1/4 cis./hr.
rate of B = 1/6 cis./hr.
rate of C = 1/8 cis./hr.
total rate = 1/4+1/6-1/8 = 7/24 cis./hr.
the cistern will be full in 24/7 = 3 3/7 hr. = 3 hours 26 minute

Like? Yes (3) | No   

Arijit Acharyya   9 years AGO

per hour work=(1/4+1/6-1/8)=7/24
the cistern will be full in=24/7 hours
3 hours 26 minute

Like? Yes (4) | No (1)  

Nilanjan Mondal   9 years AGO

in 1hr, csitern filled 1/4+1/6-1/8=7/24
total time = 1 / (7/24) =24/7 = 3 hr 26min

Like? Yes (3) | No   

KRISHNA CHANDRA UPADHYAY   9 years AGO

Net filling in 1 hour = ((1/4)+(1/6)-(1/8))
= 7/24
Therefore, Time taken to fill the cistern = (24/7)hrs.
= 3 hrs. 26 min.
HENCE, OPTION (7) IS CORRECT.

Like? Yes (3) | No (1)  

Tark Patel   9 years AGO

Total filling in 1 hour,
(1/4 + 1/6) - 1/8 = 7/24

Time taken to fill the cistern = ( 24/7 ) hr. = 3 hour 26 min

Like? Yes (2) | No   

Navneet Kaur   9 years AGO

7x=24
x=24/7=3hour 26 min

Like? Yes (2) | No   

MD SOHAIL AKHTER   9 years AGO

let cistern be full in x hr
A/Q
x/4+x/6-x/8=1
so we get x=3hr 26min

Like? Yes (2) | No   

PAWAN KUMAR   9 years AGO

time taken to fill the tank = 1/(1/4+1/6-1/8)
= 1/{ (6+4-3)/24 }
= 24/7 hrs = 3hrs 26 min

Like? Yes (2) | No   

RAJIB BANERJEE   9 years AGO

1/4+1/6-1/8=7/24 part full in 1 hour
so,full part filled in 24/7 hours=3hours 26 minutes

Like? Yes (2) | No   

BITU KUMAR NIRALA   9 years AGO

cistern will be full on=1/((1/4)+(1/6)-(1/8)) hr.
=3 hour 25.71 minutes
=3 hour 26 minutes(approx)
Answer:-3 hour 26 minutes(option:-7)

Like? Yes (3) | No (1)  

BHANU KUMAR   9 years AGO

work done by A,B,C in 1hr=(1/4)+(1/6)-(1/8)=7/24
hence cistern will be full in 24/7=24*60/7=205.7=206min=3hr26min

Like? Yes (2) | No   

SUNITEE GARIMA   9 years AGO

A's 1 hour work =1/4,B's 1 hr work =1/6,C's 1 hr work =1/8
total work done by A,B,C in 1 hr in filling the tank =(1/4+1/6)-1/8=7/24
total time taken to fill the tank by A,B,C=24/7 hr=3hr 25.7 mint

Like? Yes (2) | No   

Ajay Kumar Gupta   9 years AGO

net filling per hour=1/4+1/6-1/8=7/24
time taken to fill the cistern=24/7 hours
=3 hr 26 min

Like? Yes (2) | No   

naina   9 years AGO

A's 1 hr work =1/4
B's 1 hr work = 1/6
C's 1 hr work = -1/8
a+b+c's work = 1/4+1/6-1/8=3 hr 26 min

Like? Yes (2) | No   

Ravi Bhalani   9 years AGO

Net part filled in one hour=(1/4 +1/6 -1/8)=7/24
The tank will be full in 24/7 hrs=3 hrs 26 min

Like? Yes (2) | No   

HARDIP BHALANI   9 years AGO

Net part filled in one hour=(1/4 +1/6 -1/8)=7/24
The tank will be full in 24/7 hrs=3 hrs 26 min

Like? Yes (2) | No   

ANKUR ANAND   9 years AGO

In 1 hr (1/4+1/6-1/8)=7/24 tank can b filled
So total tank can b filled in 24/7 hrs=3 hrs 26 min.

Like? Yes (2) | No   

Harshad    9 years AGO

Net part filled in one hour=(1/4 +1/6 -1/8)=7/24
The tank will be full in 24/7 hrs=3 hrs 26 min

Like? Yes (2) | No   

Kushagra Tiwari   9 years AGO

Net filling in 1 Hour = (1/4 + 1/6 - 1/8)
that is = 7/24


therefore time taken to fill the Cistern = (24/7)hours
thay is = 3 hrs and 26 mins

Like? Yes (2) | No   

Abhishek Vishwakarma   9 years AGO

Net filling in 1 Hour = (1/4 + 1/6 - 1/8)
that is = 7/24


therefore time taken to fill the Cistern = (24/7)hours
that is = 3 hrs and 26 mins

Like? Yes (2) | No   

ABHIJIT DUTTA   9 years AGO

Net part filled in 1 hour = (1/4 + 1/6 - 1/8) = 7/24

Therefore, total time taken to fill the tank = 24/7
= 3 .428 hours
= 3 hours 26 minutes

option 7)

Like? Yes (2) | No   

azharshahid01@gmail.com   9 years AGO

Pipe A'll fill in 1 hour= 1/4
Pipe'll fill in 1 hour=1/6
Pipe'll empty in 1 hour= 1/8
So, filled cistern in 1 hour(60 minutes)= 1/4+1/6-1/8= 7/24
7/24 part of cistern fill in 60 minutes.
So, full part of cistern'll fill in= (60*1)/(7/24)= 205.71(206 approx)
206 minutes is equal to 3 hours 26 minutes

Like? Yes (2) | No   

Devendra Marghade   9 years AGO

1 hour filling=(1/4)+(1/6)-(1/8)= 7/24
So cistern will be full in 24/7 =3 3/7 Hrs
=3 hours (3/7)*60 min. ~ 3 hours 26 minute

Like? Yes (2) | No   

ALOK KUMAR   9 years AGO

in 1 hour tank full=(1/4+1/6)-1/8=7/24

total time reqired=24/7 hour=(24/7)*60=3hour26min

Like? Yes (2) | No   

RAJEEV KUMAR   9 years AGO

(1/4+1/6-1/8)y=1
y=24/7
3hr 26miniute

Like? Yes (2) | No   

Rashmi bharti   9 years AGO

24/7 hours=3 hrs 26 mins

Like? Yes (2) | No   

avimanyu kumar   9 years AGO

ans is hr 15 min

Like? Yes (2) | No   

Urvashi Jain   9 years AGO

Time taken by tap A to fill the cistern = 4 hours.

Work done by tap A in 1 hour = 1/4

Time taken by tap B to fill the cistern = 6 hours.

Work done by tap B in 1 hour = 1/6

Work done by (A + B) in 1 hour = (1/4 + 1/6) = 12/5
c work hour=-1/8
Therefore, time taken by (A + B + C) to fill the cistern = 7/24
Thus, tank will be filled completely in 24/7 hours, when all the three are opened togethe
3 hour 26 Minute

Like? Yes (2) | No   

sourav majumder   9 years AGO

time needed=1/(1/4+1/6-1/8) hours

Like? Yes (2) | No   

JAIN   9 years AGO

in 1 hour A completes 1/4 i.e. 25% positive work
in 1 hour B completes 1/6 positive work
in 1 hour C completes 1/8 negative work
So, total work completed by A, B and C is 1/4 + 1/6 - 1/8
7/24
so total time = 24/7 = 21/7 + 3/7 = 3 hour + 3*60/7 = 3 hours + 26min approx.

Like? Yes (2) | No   

Chaturbhuja Sai   9 years AGO

the exact ans is 25.7 . approx 3hr 26 min

Like? Yes (2) | No   

satish   9 years AGO

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60
The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Like? Yes (2) | No   

LOGAN WOLVERINE   9 years AGO

1/4+1/6-1/8=24/7
24/7=3+3/7
ans 3 hours and 26 minute

Like? Yes (2) | No   

shubham mittal   9 years AGO

rates of a,b,c are 6, 4, and -3 resp. so to complete work of 24 time taken will be 24/(6+4-3)= 24/7 hrs

Like? Yes (2) | No   

Udhaya kumar   9 years AGO

from given
x(1/4+1/6-1/8) = 1
x = 3 3/7
x = 3hours 25.7minutes.........................

Like? Yes (2) | No   

Mukul   9 years AGO

x(1/4+1/6-1/8)=1
x=48/14
convert it into hrs and minutes
we get
3 hrs 26 min

Like? Yes (2) | No   

nishant kumar   9 years AGO

efficincy=1/4=1/6-1/8=7/24
time taken=24/7=3hrs 26 min

Like? Yes (3) | No (2)  

Yogesh   9 years AGO

=1/4+1/6-1/8
=(6+4-3)/24
=7/24
=24/7 is the time in which the tank is full.
now convert it into minutes
from this
24/7=3 hours and 26 minutes

Like? Yes (2) | No (1)  

Pranay Mukhopadhyay   9 years AGO

net part filled in 1 hr=(1/4+1/6-1/8)=7/24
so, tank filled in 24/7 hrs=3hrs 26mins

Like? Yes (1) | No   

Manikumar R   9 years AGO

(1/4+1/6-1/8)hrs=3.26min

Like? Yes (1) | No   

Swechchha Agarwal   9 years AGO

A fills 1/4th cistern in 1 hour and similarly B fills 1/6th cistern and C empties 1/8th cistern in 1 hour.
Part of cistern filled in 1 hour when all taps turned on= 1/4+1/6-1/8=7/24
so, cistern will be filled in 24/7 hours i.e. 3 hours 25 minutes 42 seconds = 3 hours 26 minutes (approx.)

Like? Yes (1) | No   

Aditya Kumar   9 years AGO

to empty one unit when all are open : (1/4 + 1/6 ) - 1/8 =7/24 .
so the total time taken is 24/7 hrs.

Like? Yes (1) | No   

sashank   9 years AGO

By L.c.m method....L.CM of 4,6,8 is 24...ie., A=6 UNITS,B=4,C=3...
in 1 hour if all three taps are opened=7 units can be filled(6+4-3)=7UNITS...TOTAL 24 UNITS....TIME TAKEN =24/7=3h 26M

Like? Yes (1) | No   

palasiva   9 years AGO

4 6 -8
lcm 24
6 4 -3=7
24/7= 3 hours 26 minute

Like? Yes (1) | No   

Rahul shaw   9 years AGO

Together they can fill pipes in = (1/4)+(1/6)-(1/8) = 7/24.
So, 24/7 = 3.43 hrs. = 3 hrs. 26 min.

Like? Yes (1) | No   

veerareddy aasamthavva   9 years AGO

1/4+1/6-1/8=7/24
then 24-7=3hours26minute

Like? Yes (1) | No   

Mogilipuri.Harish   9 years AGO

net part filled in 1 hour=(1/4+1/6-1/8)=>7/24
tank will fill 24/7=3 3/7
3 hours 26 minute

Like? Yes (1) | No   

Anurag Krishna   9 years AGO

(a+b+c)'s 1 hour work=7/24
since 7/24 filled in 1 hour
so 1is filled in 24/7 hour
i.e. 3 hour 26 sec

Like? Yes (1) | No   

M.Venkata Manish   9 years AGO

A-4
B-6
C-(-8)
LCM of 4,6,8 is 24
so A can fill 6 liters of water in tank per hr
B can fill 4 liters of water in tank per hr
C can empty 3 liters of water in tank per hr
So all together can fill 6+4-3=7 liters of in tank per hr.
Here the total amount of water in tank is 24.
No of hrs=24/7=3.42=3hrs 25.2 minutes

Like? Yes (1) | No   

Pranoy Bej   9 years AGO

1/4+1/6-1/8=7/24
so time taken to fill the cistern =24/7 = 3 hours 26minute

Like? Yes (1) | No   

sabir ahmd   9 years AGO

if all pipes remain open ,
then work done will be = 1/4+1/6-1/8=7/24

so, total time is needed to full cistern =24/7= 3 hours 26 minute

Like? Yes (1) | No   

surya   9 years AGO

1/4+1/6-1/8

Like? Yes (1) | No   

ravindra   9 years AGO

TIME TAKEN TO FILL IS
1/4+1/6-1/8=3 3/7
3+(3/7*60)=3HOURS 26 MINUTES

Like? Yes (1) | No   

Varunraj Reddy   9 years AGO

1/4+1/6-1/8

Like? Yes (1) | No   

nagoorvali Shaik   9 years AGO

1/4+1/6-1/8=7/24
24/7 is approx 3 hours 26 mints

Like? Yes (1) | No   

SUREKHA   9 years AGO

work it out....

Like? Yes (1) | No   

Pushpendra singh chundawat   9 years AGO

let full tank be filled in x hr,then
(x/4+x/6-x/8=1)
x=24/7
3hr26min

Like? Yes (1) | No   

Nitin Srivastava   9 years AGO

let x be time to fill and v be volume
then

x(v/4+v/6-v/8)=v
x/4 + x/6 - x/8 = 1
6x+4x-3x/24=1
x=24/7
x= 3 hours 26 minute

Like? Yes (1) | No   

Math Lovers   9 years AGO

total time = 1/(1/4 + 1/6 - 1/8) = 24/7 hours

Like? Yes (1) | No   

PRIYANK BHARGAVA   9 years AGO

1/4 + 1/6 - 1/8 === 7/24
24/7 hrs = 3 hr 26 minutes

Like? Yes (1) | No   

K S SREEKRISHNAN   9 years AGO

Net part filled in 1 hour 1/4+1/6-1/8=7/24
therefore tank wil b full at 24/17 hrs
=3 hrs 26 minutes(approx)

Like? Yes (1) | No   

Ranjan kumar   9 years AGO

48/14 hrs (1/(1/4 + 1/6 - 1/8))

Like? Yes (1) | No   

kowsalya   9 years AGO

3hr 21 litr
3hr 30min 24.5 litr
so.

Like? Yes (1) | No   

anu mishra   9 years AGO

1/4+1/6-1/8 = 7/24... therefore time taken = 3 hours 26 minutes approx

Like? Yes (1) | No   

S. Singh   9 years AGO

1/4+1/6-1/8=7/24 in on hour

Like? Yes (1) | No   

SHASHANK VERMA   9 years AGO

total work=1/4+1/6-1/8=7/24

total time=24/7=3.4257or 3h25minute

Like? Yes (1) | No   

hari   9 years AGO

for 1 hour tank filled 7 parts outof 24parts

so 3h26min tank fully filled

Like? Yes (1) | No   

Niveditha Ravichandran   9 years AGO

A=4 hr
B=6 hr
C=8 hr
lcm for 4,6,8= 24 litres

that is A can fill 6 litres/hr
B can fill 4 litres/hr
C can fill -3 litres/hr
A+B+C = 6+4-3= 7 litres/hr

total time taken to fill 24 litres is 24/7= 3 hr 3/7 min
=3hr 26 min

Like? Yes (1) | No   

MANU   9 years AGO

from question
1/4+1/6-1/8=7/24
so tme taken to fill the cistern=24/7 hr=3 hr 26 minute

Like? Yes (1) | No   

rutuja   9 years AGO

LCM(4,6,8)=24
Now, 24/4=6
24/6=4
24/8=3
A+B-C=6+4-3=7
24/7=3 hrs 26 minutes

Like? Yes (1) | No   

Simbaa   9 years AGO

together all of three pipes fills 7l water in one hour....so to fill 24l of water 3hour26min are required

Like? Yes (1) | No   

LOKESH SAMANT   9 years AGO

A cistern can be filled by pipes A and B in 4 hours and 6 hours respectively. When full, the tank can be emptied by a pipe C in 8 hours. If all the taps be turned on at the same time, the cistern will be full in 24/7 hr

Like? Yes (1) | No   

sriram   9 years AGO

(1/4)+(1/6)-(1/8)=3h26m

Like? Yes (1) | No   

RAVI RANJAN   9 years AGO

1/4+1/6-1/8 =7/24
so time is 24/7 hours

Like? Yes (1) | No   

Rahul rahul   9 years AGO

pipe A abd B can fill 5/12 cistern in an hour
and pipe C can empty 1/8 in an hour
so apply
5/12 *x - 1/8*x = 1
if 'x' is the time required

Like? Yes (1) | No   

Amit kumar   9 years AGO

1/4+1/6-1/8=3.428 which means 3hr26min

Like? Yes (1) | No   

Shaban Ahmad   9 years AGO

in 60 minutes pipe A fills 1/4 of the cistern
in 60 minutes pipe B fills 1/6 of the cistern
hence, in 60 minutes pipes A and B combinedly fill 1/4+1/6=5/12 of the cistern.
in 60 minutes pipe C empties 1/8 of the cistern
hence, in 60 minutes 5/12-1/8=7/24 of the cistern is filled when all taps are on.
hence , the time required to fill the cistern fully when all the taps are on=60*24/7=205.7 minutes=3 hours 26 minutes(approx.)

Like? Yes (1) | No   

Suuhel   9 years AGO

1/6 +1/4=5/12-1/8=7/24 i.e. 24/7 hrs or 3 hrs 26 minutes

Like? Yes (1) | No   

kajol nigam   9 years AGO

1/6+1/4-1/8=7/24
3 hours 26 min

Like? Yes (1) | No   

DIVANSHU   9 years AGO

3 hr 26 minutes

Like? Yes (1) | No   

vaishnavi   9 years AGO

A's 1 hour work=1/4
B's 1 hour work=1/6
C's 1 hour work=1/8
work done by A,B,C in 1 hour=(1/4)+(1/6)-(1/8)=7/24
time taken by A,B,C to full the cistern =24/7=3 hours 26 minute

Like? Yes (1) | No   

Narendra Jadon   9 years AGO

Time taken to fill the cistern is:
1/4 + 1/6 - 1/8
=(6+4 -3)/24
=7/24
24/7 hours
3 hour 26 minute

Like? Yes (1) | No   

shashikanth   9 years AGO

1/4+1/6-1/8=7/24

Like? Yes (1) | No   

Shikha   9 years AGO

A's 1hr work=1/4
B's 1 hr work=1/6
C's 1hr work=1/8
Total work done in 1 hr=(1/4)+(1/6)-(1/8)=7/24
total time taken to complete the work=24/7=3hours 26 min

Like? Yes (1) | No   

Promit Saha   9 years AGO

net work done in 1 hr is 1/4+ 1/6 -1/8=7/24
total time taken to complete the work is 1/(7/24) hrs=24/7 hrs
=3 hrs 25 mins 12 secs which is approximated to 3hrs 26 secs

Like? Yes (1) | No   

Akshay A. Bipalliwar   9 years AGO

Time taken by first tap to fill the cistern = 4 hours.

Work done by first tap in 1 hour = 1/4

Time taken by second tap to fill the cistern = 6 hours.

Work done by second tap in 1 hour = 1/6

Time taken by third tap to empty the cistern = 8 hours.

Work done by second tap in 1 hour = (-1/8)

Therefore Total Work done=1/4+1/6-1/8=7/24
Cistern will be full in 24/7 i.e.,3 hours 26 minutes

Like? Yes (1) | No   

aman kumar tiwari   9 years AGO

answer should be 24/7 hours

Like? Yes (1) | No   

mukesh   9 years AGO

1/4+1/6-1/8
7/24
so total time to complete the the work=24/7=3 3/7=3 hours 26 minutes

Like? Yes (1) | No   

Jasmita Parmar   9 years AGO

A,B and C's 1 hour work = 1/4 + 1/6 - 1/8 = 7/24
So three tapes simultaneously can fill cistern in 24/7 hours = 3 hours 26 minutes

Like? Yes (1) | No   

RANA ROY   9 years AGO

it's by time and work i have calculated

Like? Yes (1) | No   

arijit roy   9 years AGO

if all pipes work together then per hour tank filled=(1/4+1/6-1/8) partial
so for full ... comlete in 3hr 26 min

Like? Yes (1) | No   

Sneha Goel   9 years AGO

1/4+2/6-1/8

Like? Yes (1) | No   

adarshankit   9 years AGO

A and B can fill the cistern in 1 hour=1/4+1/6
=5/12
again it is emptied by c in 1 hour=1/8
so it can be filled in 1 hour= 5/12-1/8
3.26 hr.

Like? Yes (1) | No   

Rituparna Banerjee   9 years AGO

net part filled in 1hour=(1/4+1/6-1/8)=3/24
the cistern will be full in 24/3 hours i.e. in 3 hours 26 minute

Like? Yes (1) | No   

Dipak Singh   9 years AGO

1/(1/4)+(1/6)-(1/8)=24/7=3 hrs 25.7mins

Like? Yes (1) | No   

yatish kumar sharma   9 years AGO

(1%6+1%4)-1%8= 3 hours n 26 min

Like? Yes (1) | No   

MRITUNJAY KUMAR   9 years AGO

t(5/12-1/8)=1
t= 3hrs 26 min.

Like? Yes (1) | No   

shiv pujan   9 years AGO

amount filled in 1 hr=(1/4+1/6-1/8)=7/24
hence time to full tank=24/7=3:26hr
hence option 7)

Like? Yes (1) | No   

muthu mari   9 years AGO

3 hours 26 minute.
net part filled in 1 hour=(1/4+1/6-1/8)=7/24 L
the tank will be full in 24/7 hours=3 hours 26 minutes

Like? Yes (1) | No   

T.VIGNESWARA REDDY   9 years AGO

the lcm is 24 a-- 6
b--- 4
c-- -3
so 24/7 3:25:42

Like? Yes (1) | No   

Ramu Giri   9 years AGO

net part filled in 1 hour=(1/4+1/6-1/8)=7/24
the cistern will be full in 24/7 hrs=24/7=3 hrs 26 minute

Like? Yes (1) | No   

LOKENDRA SINGH RAO   9 years AGO

1/4+1/6-1/8=7/24
whole part will be filed in 24/7.
which equal to 3 hours 25.71 min

Like? Yes (1) | No   

Rayapureddy V Sai Kiran   9 years AGO

in 1 hour volume of tank filled=(1/4)+(1/6)-(1/8)
=0.2916666667
total tank can be filled in 'x' hours

x=1/0.2916666667
= 3.428hours
=3 hours 26 minutes

Like? Yes (1) | No   

adarsh kumar yadav   9 years AGO

A fills per hour 1/4
B " " 1/6
C empties 1/8
then
1/4+1/6-1/8 should be 1
so on solving
ans 3 hours 26 minute

Like? Yes (1) | No   

shabana   9 years AGO

A+B+C 1 hr work=(1/4+1/6)-1/8=7/24
7/24 work completed in 1 hr
total work completed in=24/7
3 hr 26 min ans

Like? Yes (1) | No   

sudipta maji   9 years AGO

the cistern will be fill in 1 hour 1/4+1/6-1/8=7/24
so the time taken to fill cistern is 24/7=3 hour 26 minute

Like? Yes (1) | No   

S B HARISH   9 years AGO

net work done in 1 hr=(1/4)+(1/6)-(1/8)=7/24
total work done=24/7=3 hr 26 mins

Like? Yes (1) | No   

RITESH SINGH   9 years AGO

in 1 hr pipe A fills 1/4part
similarly in 1 hr pipe B fills 1/6part
in 1 hr pipe C empties 1/8part
so in 1 hr part of the cistern filled=(1/4+1/6-1/8)=7/24
time taken to fill the cistern =24/7hr=3hr 26min

Like? Yes (1) | No   

Vinayak Chaskar   9 years AGO

In 1 hr, the cistern will be filled = 1/4 + 1/6 - 1/8 ;
Now
Let in X hr cistern will be fully filled = 1;
X= 1/(1/4 + 1/6 - 1/8);
X = 24*60/7 (in minute);
X = 3 hours 26 minute.

Like? Yes (1) | No   

Dikesh Kumar Gumansingh   9 years AGO

1/4+1/6-1/8=7/24=0.342
so 3.42 hr =3 hr 26 min approx

Like? Yes (1) | No   

Tulasi Prasanna Kumar Yanamadala   9 years AGO

TOTAL=(1/4)+(1/6)-(1/8)
=7/24
24/7 Hours means... 3 3/7 hours means ...3 hours 25.71 min..
3 hours 26 min

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abhik k. dey   9 years AGO

A can fill in 4 hrs . so its efficiency is 1/4;
for B it is 1/6 as it fills in 6 hrs, and
for C efficiency is 1/8, as it can empty in 8 hrs,

so if all three tapes are open then in 1 hr the cistern will be filled (1/4+1/6-1/8)=7/24
so the CISTERN will be filled in 24/7 hrs= 3 hrs and 25.71428 minutes.=3 hrs and 26 minutes

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