In a class, the number of boys is more than the number of girls by 12% of the total strength. The ra

Ishan Pushkarna   9 years AGO

Suppose the no. of students in the class is 100
So according to the question the no. of boys are 12 more than the no. of girls.
Therefore if x is the no. of girls then x+12 is the no. of boys.
Now, x+x+12=100 i.e. x=44 no. of girls
& no. of boys will be 44+12=56.
Therefore 56/44= 14:11.

Like? Yes (40) | No (7)  

pritika singh   9 years AGO

no. of grls be x
boys=100-x
100-x=x+12
x=44
g=44 b=56
g/b=14/11

Like? Yes (54) | No (24)  

Kushagra Tiwari   9 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (33) | No (11)  

Shreya Tiwari   9 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (16) | No (6)  

Arijit Acharyya   9 years AGO

let, the number of boys and girls are b & g respectively
b=g+ 12 of (b+g)
b=g+(12/100)*(b+g)
b=g+(3/25)*(b+g)
by calculating....
b : g = 14 : 11

Like? Yes (9) | No (1)  

Divya Dawar   9 years AGO

let total students be 100, so boys more than girls is 12
let no of girls be x , so boys are x+12
ATQ, x+x+12=100
we get girls =44, boys =56
so boys:girls=14:11

Like? Yes (7) | No (1)  

Udhaya kumar   9 years AGO

let x as number of boys and y as number of girls
hence from given
x = y + 0.12(x+y)
by solving we get x / y = 1.12 / 0.88 = 14 / 11...

Like? Yes (6) | No   

shubhi vijayvergia   9 years AGO

total no. of students =100
x be no of girls then x+12 will be boys
x+x+12=100
x=44
56:44
14:11

Like? Yes (5) | No   

Udaybhan Viswkarma   9 years AGO

B-G=12%of(B+G)
B/G=112/88
B/G=14/11
So,9)14:11 is the correct answer.

Like? Yes (4) | No   

shubham   9 years AGO

suppose total is 100
the strenth of boys is 12% of total strength . so boys will be 12% more from 100 total student



now we substract 12 from 100 and get 88 now half of 88 will be 44 which same for boys and girls


now we add 12 in 44 boys and get 56 boys


so the ratio is boys and girls 56:44 = 14:11

Like? Yes (3) | No   

PRAVIN PRAJAPATI   9 years AGO

B-G=12%
B+G=100%
B=56%
G=44%
B:G=56:44=14:11

Like? Yes (3) | No   

sai naveen vanapalli   9 years AGO

b=g+12%(b+g)
b/g/= 14/11

Like? Yes (2) | No   

Chirag Ranjan Lahiri   9 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
So, x-y = (3/25)(x+y)
25x-25y = 3x+3y
22x = 28y
x/y = 28/22 = 14/11
So the required ratio will be - boys:girls = x:y = 14:11(answer)

Like? Yes (2) | No   

Ankit Sirohi   9 years AGO

x-y= (12/100) *(x+y)..i.e
25x-25y=3x+3y
=> x/y=14/11 ...14:11 option 9 ..is d answer

Like? Yes (2) | No   

H.Aparna Rao   9 years AGO

let x=boys and y=girls
then, x=y+12%(x+y)
x=y+0.12x+0.12y
0.88x=1.12y
x/y=112/88=14/11

Like? Yes (2) | No   

SOURABH   9 years AGO

let no. of boys be x and that of girls be y
total no. of students=x+y
x-y=12%(x+y)
on solving we get,
x:y=14:11

Like? Yes (3) | No (1)  

Aishwarya Chandra   9 years AGO

Let the no. Of boys = X
& no. Of girls = Y
Then,
X = Y + 12% (X + Y)
X = Y + .12 X + .12 Y
X/Y = 14/11

Answer = 14/11

Like? Yes (2) | No   

nikhil jaiswal   9 years AGO

let boys(x)+girls(y)=100
then given x-12=y
2x=112
x=56;y=44
x:y::56:44=14:11

Like? Yes (1) | No   

ravi prakash   9 years AGO

let total strength be 100 then
x+(x+12)=100
x=44(girls)
therefore boys =56
therefore ratio=14/11

Like? Yes (1) | No   

V.Latha   9 years AGO

b+g = 100
b = g+12% of 100
g+12+g = 100
2g = 88
g = 44
b = 100-44 = 56
b:g = 56:44 = 14:11

Like? Yes (1) | No   

TINKU MITTAL   9 years AGO

let boys=x
girls= y
so, x= y+ 12% of (x+y)
solving this, x:y= 14:11

Like? Yes (1) | No   

sudhakar   9 years AGO

let's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

Like? Yes (2) | No (1)  

aman   9 years AGO

Let total strength be x
Let girls be y
Boys = y+0.12x
Total strength = boys + girls
x=y+0.12x+y
0.88x=2y
x:y=25/11
Total:girls=25/11
Boys:girls = (25-11)/11
Boys:girls = 14:11

Like? Yes (1) | No   

Sanchit Kapoor   9 years AGO

Let the total strength be x and
number of girls be y
Then number of boys=x-y
But x-y=12x/100+y
On solving x=200y/88
So ratio of boys to girls=x-y/y
(200y/88 -y)/y
=14:11
So option 9 is correct

Like? Yes (5) | No (4)  

Durgesh Tripathi   9 years AGO

Assume no of boys=b and no of girls=g
total strength=b+g
given condition
b=g+(12(b+g)/100)
b=g+0.12b+0.12g
(0.88)b=(1.12)g
=> b/g=14/11

Like? Yes (1) | No   

vinit   9 years AGO

let the total number be 1200;
now 12% of total strength 1200*12/100=144;
hence 1200-144=1056/2
528+144=672 (total number of boys)
528 (total number of girls)
672:528
14:11 ans

Like? Yes (2) | No (1)  

ramakrishnateja   9 years AGO

let the total strength is 100%. then strength of boys and girls is x&y. then boys %=100x/x+y
girls %=100y/x+y. given that the difference is12%. so 100(x-y)/x+y=12. then 88x=112y. so the ratio of boys and girls is 14:11.

Like? Yes (1) | No   

Rounak Jain   9 years AGO

Let No. of boys = b
No. of girls = g
total strength = b+g
b = g + (12(b+g)/100)
100b = 100g + 12b + 12g
b/g = 112/88
b/g = 14/11
which is the required answer.

Like? Yes (2) | No (1)  

Bhupendra Rana   9 years AGO

x=boys
y=girls
x=y+12%(x+y)
x=(112/88)y
x/y=14/11

Like? Yes (1) | No   

vishnuvardhan   9 years AGO

lat x be no. of boys,y be no. of girls
x-y=12/100*(x+y)
88x=112y
x/y=14/11

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

let total strength
ans=28:25=1200
so 12%=12*1200/100=144
so 1200-144=1056/2=528(girl)
boys=528+144=672
ratio=672:528
=14:11

Like? Yes (1) | No   

soni dabas   9 years AGO

let the total strength b 100...then boys r 56 n girls r 44...ratio comes to b...14:11...for boys:girls

Like? Yes (1) | No   

RAVI RANJAN   9 years AGO

14:11

Like? Yes (1) | No   

harini   9 years AGO

let no of boys & girls be X & Y
X-Y=12/100[X+Y]
X-Y=3/25[X+Y]
25X-25Y=3X+3Y
22X=28Y
X/Y=28/22=14/11
X:Y=14:11
option 9

Like? Yes (1) | No   

Ramesh Sriram   9 years AGO

let assume B+G=100
according to condition
B=G+(12*100/100)
B:G=56:44=14:11

Like? Yes (2) | No (1)  

Ravi Kumar Kodari   9 years AGO

let assume B+G=100
according to condition
B=G+(12*100/100)
B:G=56:44=14:11

Like? Yes (1) | No   

A Rafi   9 years AGO

let b = no.of boys, g = no.of girls, x = total strength = b + g
given that b = g + 0.12 x
x = b + g = g + 0.12 x + g => g = 0.44 x
b = x - 0.44x = 0.56x
b:g = 14 : 11

Like? Yes (1) | No   

SOURAV MUKHERJEE   9 years AGO

boys=x,girls=y;
x-y=12/100(x+y)
x:y=14:11

Like? Yes (1) | No   

ritu sameer   9 years AGO

b+g=x
g+(12100)x=b
after solving these equations if u find the ratio of b:g then the answer will be 14:11

Like? Yes (1) | No   

Ravinder Soni   9 years AGO

b=g+12/100(b+g)

b/g={ g+12/100(b+g) } / g

b/g= 1+12/100{b/g+1)

do some maths.....

(1-12/100)(b/g) = 1+12/100

b/g=112/88=14/11 ans.

Like? Yes (1) | No   

mahesh   9 years AGO

here let a=no.of boys and b=no.of girls then a=b+12%of (a+b)
a=b+0.12a+0.12b
then 0.88a=1.12b
a/b=1.12/88
a/b=14/11 which is required answer.option 9

Like? Yes (1) | No   

ANIMESH GORAI   9 years AGO

let x be the girl's percentage,
x+12 is boy's percentage
x+x+12=100
x=44
boy:girl=56:44
=14:11

Like? Yes (1) | No   

nishu kumar   9 years AGO

let total strength =x and number of girls=y then number of boys=x-y
now given,
boys=y+12/100*x
x-y=(100*y+12*x)/100
88x=200y
now x=200/88*y
subtracting y from both sides
x-y=(200-88)y/88
(x-y)/y=14/11
boys:girls=14:11

Like? Yes (1) | No   

jyoti   9 years AGO

let no of boys be x and girls be y
then x=y+12%(x+y)
x=y+0.12x+0.12y
0.88x=1.12y
x/y=14/11

Like? Yes (1) | No   

Himanshu Mittal   9 years AGO

boys percentage:56%
girls percentge:44%
boys:girls=56:44=14:11

Like? Yes (1) | No   

sujata chakraborty   9 years AGO

B=G+(12/100)X and B+G=X
DIVIDING BY G AND SUBSTITUTING X,

(88/100)*(B/G)=(112/100)

B/G=14/11

Like? Yes (2) | No (1)  

vivek   9 years AGO

Let no of boys be x and girls be y.
then total strength of class is x+y
so a/c to question,
x=y+(x+y)*12%
=> x=y+(x+y)*12/100
=> 25x=28y+3x
=> 22x=28y
so, x:y=14:11

Like? Yes (1) | No   

abhinav singh   9 years AGO

assume there is no of girls in the class =G and boys=B.
no. of boys is 12% more than girls in the class
then it will,
B=G+12/100(G+B)
B-12/100B=G+12/100G
11B=14G

ans is 25:28

Like? Yes (1) | No   

santu ghosh   9 years AGO

let
boys=x,girls=y
so,x-y=(x+y)*12/100
100x-100y=12x+12y
88x=112y
x/y=14/11
x:y=14:11

Like? Yes (1) | No   

sonu suman   9 years AGO

let the no. of boys be x
and no. of girls be y
again assume that total no. of student be 100
so we have x+y = 100
and from first case we have
x=y+(12% of (x+y))
or x=y+12
solving both we have
x= 56
y=44
so x/y = 14:11

Like? Yes (1) | No   

Gaurav Sharan   9 years AGO

b= g+0.12(b+g)
so, we get
b/g=112/88=14/11

Like? Yes (1) | No   

CHANDAN KUMAR   9 years AGO

b-g=12(b+g)/100
b/g(1-12/100)=112/100
b/g=112/88=14/11

Like? Yes (1) | No   

shree   9 years AGO

56/44=14/11

Like? Yes (1) | No   

Jagruti   9 years AGO

let total strength = 100
12% of total strength = 12
let x=no. of boys
let y=no. of girls
x+y=100
also x-y=12 (since no. of boys is 12 greater than girls)
hence x=56
y=44
ratio=14:11

Like? Yes (2) | No (1)  

Ankit   9 years AGO

No of boys =x
no of girls = y
total strength = x+y
So,
x-y=12/100(x+y)
100x-100y=12x+12y
100x-12x= 100y+12y
88x= 112y
x/y= 14/11
14:11

Like? Yes (1) | No   

yoganandan   9 years AGO

b=g+12/100(b+g)
b=g+12b/100 +12g/100
b-12b/100=g+12g/100
88b=112g
b/g=112/88
b/g=14/11

Like? Yes (1) | No   

Mahesh   9 years AGO

Let the number of girls be x%
The number of boys is (x+12)%
x+(x+12)=100
x=44
Girls percentage =44
Boys percentage = 56
Ratio of boys to girls = 56:44=14:11

Like? Yes (1) | No (1)  

Sourojit Dhua   9 years AGO

Let total no. of students= 100
Then boys= 56
girls= 44
Therefore,
ratio= 14:11

Like? Yes (5) | No (5)  

sanjeeth   9 years AGO

(14 :11)
Total = 14 + 11 = 25
boys = 14
girs = 11
12/100 * 25 = 3
No. of boys = no. of girls + 12/100 * total strength
14 = no. of girls + 3
hence no. of girls is = 14 - 3 = 11

Like? Yes (2) | No (2)  

Rashi Bansal   9 years AGO

let number of boys = x
number of girls= y
so strength of class =(x+y)

a.t.c.

x= y + 12/100 *(x+y)
25x = 25y+3x+3y
22x=28y
so x/y=14/11
n hence the ratio is 14:11 which is option (9)

Like? Yes (1) | No (1)  

Gitanjali K   9 years AGO

14:11

Like? Yes (1) | No (1)  

ragini   9 years AGO

y+12/100(x+y)=x
25y+3x+3y=25x
x/y=14/11

Like? Yes (1) | No (1)  

Sundar Kumar   9 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or 22x = 28y
or x/y=28/22=14/11=14:11
Answer: OPTION 9)14:11

Like? Yes (3) | No (3)  

BHASKAR MANDAL   9 years AGO

14/11 is the answer
let x be the no. of boys and y be no. of girls
then we can write
x=y+0.12(x+y)
divide throughout by y
x/y = 1+0.12((x/y)+1)
=> (x/y) (1-0.12) = 1+0.12
=>x/y = 1.12/0.88 = 112/88 = 14/7

so, x : y = 14 : 7
option 9 is the answer

Like? Yes (2) | No (2)  

SIDDHARTH KUMAR   9 years AGO

let total strength =100
let no. of girls=g
then no. of boys=g+12
then g+(g+12)=100
2g+12=100 =>g=44

now
boys/girls=(44+12)/44=14/11=14:11

Like? Yes (1) | No (1)  

pawan kumar   9 years AGO

Let, total student=100
so, B:G=56:11
=14:11

Like? Yes (1) | No (1)  

Abhishek Vishwakarma   9 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (1) | No (1)  

Md.Sultan Khichi   9 years AGO

Let num of boys and girls are x and y.
So x=12/100*(x+y)+y
x/y=14/11
Ans 14:11

Like? Yes (1) | No (1)  

T.Aravinth kumar   9 years AGO

x+0.12*(x+y) > y
solve
x:y
14:11

Like? Yes (1) | No (1)  

Deepu Kumar   9 years AGO

Let The number of Boys be X and no.of Girls be Y.
then,
X=y+12%(X+Y)
X=Y+0.12X+0.12Y
0.88X=1.12Y
so X/Y=112/88=14/11
So The option 9 is correct.

Like? Yes (1) | No (1)  

anand agarwal   9 years AGO

b-g=(3/35)*(b+g)
if we solve it we get
b/g=14/11

Like? Yes (1) | No (1)  

Dr.Dipin Singh   9 years AGO

If there are total 100 students in class, then there are 56 boys and 44 girls because the number of boys is more than the number of girls by 12% of the total strength.
hence ratio = 56:44= 14:11

Like? Yes (1) | No (1)  

vartika    9 years AGO

LET TOTAL STRENGTH BE X.
AND number of boys be b and gals be g.
then according to question,
b+g=x
and b-g= 0.12x
solving above equations we get, b=0.56x
and g= 0.44x
=> reqd ratio= b/g= 14/11

Like? Yes (1) | No (1)  

PAWAN KUMAR   9 years AGO

let the no of boys be x and the no of girls be y respectively.
total strength = x+y
12% of total strength = 0.12*(x+y)
now,
x-y = 0.12*(x+y)
=> 0.88x = 1.12y
=> x:y = 1.12 : 0.88 = 14:11

Like? Yes (1) | No (1)  

shekhar suman   9 years AGO

let total strength=100
then,B=G+12----(1)
and B+G=100----(2)
from eq. 1 and 2
G=44
so B=56
now, B/G=56/44=14/11

Like? Yes (1) | No (1)  

Anmol Srivastava   9 years AGO

TAKING TOTAL STUDENTS AS 100, TAKING NUMBER OF BOYS AND GIRL IN SUCH A WAY THAT THE DIFFERENCE BETWEEN THEIR NUMBER BE 12% OF TOTAL STRENGTH i.e. 12 IN THIS CASE SO BOYS=56 AND GIRLS=44, THE RATIO COMES TO BE 14:11.

Like? Yes (1) | No (1)  

Mani kandan   9 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 325 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=2822=1411=14:11

Like? Yes (1) | No (1)  

Surit Datta   9 years AGO

let the total strength is 100
number of boy = B
number of girl = G
according to the question
B = G +12
and
B + G = 100
solving this we get,
B = 56
G = 44
so there ratio is 14 : 11
That's it..

Like? Yes (1) | No (1)  

Nayan Agrawal   9 years AGO

Let the number of boys be B and number of girls be G
B = G + 12/100(B+G)
22B = 28G
B:G = 14:11

Like? Yes (1) | No (1)  

siddhartha sadhu   9 years AGO

let boys=x;
and girl=y;
x-y=(12/100)*(x+y)
x/y=14:11

Like? Yes (1) | No (1)  

ananth   9 years AGO

from the options 14:11
14+11=25
12% off 25 =3
14-11=3
therefore 14:11 is the answer

Like? Yes (1) | No (1)  

SHUBHAM KUMAR   9 years AGO

THROUGH AANSWERS

Like? Yes (1) | No (1)  

ravi prakash   9 years AGO

let no of boys=b
no of girls=g
and total strength=x
b+g=x
b-g=12%of x
=(12/100 )*x
on solving two equation
b=56/100
and g=44/100
b/g=56/44
=14:11

Like? Yes (1) | No (1)  

LIPIKA DAS   9 years AGO

let x and y be the no. of boys and girls respectively.
A/q
x-y=12% 0f (x+y)
x-y=12/100*(x+y)
x/y=14/11hence 14:11

Like? Yes (1) | No (1)  

Ritika Shrivastava   9 years AGO

Let total students be 100
So 12% of 100=12
No of boys b=12+g
No of girls g
b+g=100
g+12+g=100
G=44
B=56
14:11

Like? Yes (1) | No (1)  

shayali bhartiya   9 years AGO

no of boys =b
no of girls=g
b=g+12/100(b+g)
b/g=14/11

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   9 years AGO

56/44=14/11

Like? Yes (1) | No (1)  

sharathbabu   9 years AGO

Let the number of by be X and number of girl be Y
then X= Y+12%(X+Y)
0.88X = 1.12Y
X/Y = 112/0.88
= 14/11

Like? Yes (1) | No (1)  

Anoop Tiwari   9 years AGO

Let total number of student in the class=100
than number of boys=56
number of girls=44
hence ratio=56/44=14/11

Like? Yes (1) | No (1)  

Akshay   9 years AGO

let total number of student =100
let number of boys=x
number of girls=y
but number of boys x=y+12
then x+y=100
y=44
x=56
x=y=56/44=14/11

Like? Yes (1) | No (1)  

Partha Pratim Mahata   9 years AGO

Let's
Total=100
12% of total strength=12
let the no of boys =B
the the no of Girls=100-B
so,B=100-B+12
B=56
No of girl =44
so ratio is 56:44=14:11

Like? Yes (1) | No (1)  

Chandra chur anand   9 years AGO

x=(100-x)+12
so x=56 i.e. no. of boys
so 100-56=44 no. of girl
ratio=56/44=14/11 so 14:11 is ans

Like? Yes (1) | No (1)  

Hradesh patel   9 years AGO

let boy=x;girl=y;total strength=100;
x+y=100;
x=y+12;
solve ........get x=56,y=44;
ratio is 14:11

Like? Yes (1) | No (1)  

Rohan   9 years AGO

its simple,
x= y+(x+y)*12/100
after solving, x:y= 14:11

Like? Yes (1) | No (1)  

anandhakumar   9 years AGO

t's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

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selvakumar   9 years AGO

t's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

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sravs   9 years AGO

let the total students =x
number of boys =y, number of girls=x-y
y=(x-y)+(12*x/100)
we get y=56*x/100; x-y=44*x/100
y/x-y = 56/44 = 14/11

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Anjali   9 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 325 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=2822=1411=14:11

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ashok   9 years AGO

14/11

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Nikhil Awasthi   9 years AGO

let total marks be 11x +14x that is 25x.. and 12% of that is 3.
so no of boys are 3 more than girls if we see ratio. So 9th i.e. 14/11 i think is correct

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Urvashi Verma   9 years AGO

B=12%T+G
B=0.12(B+G)+G
so, B/G=1.14/0.88
B/G=14/11

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anuj gupta   9 years AGO

14:11

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thasleema   9 years AGO

According to the question Difference between the two numbers is 12% of the total

=> x-y=(12/100)(x+y)
=>100x-100y=12x+12y
=>88x=112y
=>x/y=14/11

ans=14:11

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priya saha   9 years AGO

ansr (9)14:11
soln:
let the total no. of students be 100
let no. of boys be x and girs be y
12% of 100=12
so x=y+12 ------1
and x+y=100 ------2
so putting value of x from equation 1 to equation 2 we get
y+12+y=100
2y+12=100 or 2(y+6)=100
or y+6=50
hence y=44 so x=56
so boys:girls =x:y=56:44=14:11

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abhishek   9 years AGO

Answer=14:11

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Soham Dalwadi   9 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=28/22=14/11=14:11

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niraj   9 years AGO

let total strngth is 100
14*4:11*4
56:44
100*12/100=12
44+12=56

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Kethineni Vinodh   9 years AGO

by verification:
14/25*100=56
11/25*100=44

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AMREEN   9 years AGO

let boys=B
Girls=G
Total no. of stuidents=x
B+G=x
B=G+(x*12/100)
G=x-B
after solvng these 2 equation we get
B/G=14/11

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RAKESH   9 years AGO

b = g + (b+g)*12/100
=> b:g = 14:11

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AJAI AGARWAL   9 years AGO

total=100;
boys in other class=12
b=100-12=88
44 pairs of two
hence b=44+12=56
g=44
ratio=56:44
hence: 14:11

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Ramanand Yadav   9 years AGO

let total strength of claas is x.
Acc to question
x*12/100= 3x/25 boys more tahan girls.
Now x-3x/25= 22x/25 is number of both boys and giels. Now divide it by 2 i.e 22x/2*25=11x/25 number of girls.
Then boys= 11x/25+3x/25=14x/25
Now ratio (14x/25)/11x/25=14/11
i.e. 14:11

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Priya Dharshini   9 years AGO

let x be the no of students in the class.
so x be no of boys + no of girls
moreover they given that boys is more than girls by 12% of total strength .




now take x=100;
then if girls is 44
boys=44+12*12/100=44+12=56;


answer is 56:44
14:11

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mukesh agrawal   9 years AGO

112/88=14/11

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swarupa nuggu   9 years AGO

14:11

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maths hater   9 years AGO

say number of girls=x
112x/100*x=28/25

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anjali   9 years AGO

let us assume total strength of class =100
boys+girls=100
let girls be x
then boys= x+12
(x+12)+x=100
x=44
girls=44
boys=56
therefore,
ratio=boys/girls=56/44=14/11

Like? Yes (1) | No (3)