A can do a piece of work in 12 days. B is 60 % more efficient to do the same work. If both of them w

Ashish Kumar   9 years AGO

work done by A in 1 day = 1/12
B being 60% efficient
work done by B in 1 day = 1/12+(60%of 1/12) = 1/12+1/20 = 2/15
work done by A and B in 1 day = 1/12+2/15 =13/60
time taken to complete the work = 60/13 days

Like? Yes (11) | No (4)  

Kushagra Tiwari   9 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

which is in option no 6

Like? Yes (17) | No (10)  

NAVEEN KUMAR   9 years AGO

Ratio of time taken by A&B=160:100 =8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
=> 8x=5*12
=> x=15/2 days.
If both of them work together
by fraction method,
(1/12)+(2/15)=13/60
hence,
If both of them work together then the number of days required to do the same work is 60/13 days
option(6)

Like? Yes (15) | No (9)  

ananya das   9 years AGO

1 day's work for A=1/12
1 day's work for B=(1/12)*(6/10)=1/20
1 day's work of A and B=(1/6)+(1/20)=13/60
then they will complete the work in 60/13 days

Like? Yes (6) | No   

Rashmi bharti   9 years AGO

B's work in one day=2/15
so days required to do the work by both of them =1/(1/12 + 2/15)=60/13.

Like? Yes (5) | No (1)  

Anand   9 years AGO

time taken ratio = 160: 100
=8:5
8:5::12 :x ( let no of day taken by B complete)
so x= 15/2
to complete work by A and B by = 1/12 + 2/15
= 13/60
so they complete work in 60/13 days

Like? Yes (4) | No   

aman   9 years AGO

Let A efficiency be 1 , Then B efficiency is 1.6
A do in 12 days so B do it in 12/1.6 = 7.5days
Than A do in 12 days
B do in 7.5 days
Together they do in 60/13 days

Like? Yes (3) | No   

Abhishek Vishwakarma   9 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

Like? Yes (3) | No   

abhinav singh   9 years AGO

Answer: Option 6

Explanation:

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B takes x days to do the work.

Then, 8 : 5 :: 12 : x => x = (12*5)/8 => x =15/2.

A's 1 day's work = 1/12 ;

B's 1 day's work = 2/15;

(A + B)'s 1 day's work = (1/12+2/15)=13/60.
Therefore, A and B together can complete the work in 60/13 days.

Like? Yes (4) | No (1)  

ROHIT KUMAR   9 years AGO

A's 1 day work = 1/12
since B is 60% eff. than B it is written as 160% or 160/100 of A hence

B's 1 day work = (1/12)*(16/10) = 2/15
(A+B) 's one day work = 1/12+2/15 = 13/60, hence

no. of daYS required to finish the work is 60/13 ans

Like? Yes (4) | No (1)  

santosh kumar patel   9 years AGO

ratio of time taken by A and B = 160:100=8:5
suppose B alone takes X days to do a job
then 8:5 :: 12:X
8X=5*12= 15/2
both together do the job= 1/12+2/15
39/180=13/60
so taken time=60/13
ans: 60/13

Like? Yes (3) | No   

Shreya Tiwari   9 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

Like? Yes (2) | No   

manodhar   9 years AGO

Ratio of times taken by A and B = 160 : 100 = 8:5.

Suppose B takes x days to do the work.

8 : 5 :: 12 : x x = 15/2

x = 15/2 days.

Hence, B takes 15/2 days to complete the work.
Together they complete the work in d days:
1/12 + 2/15 =1/d
13/60 = 1/d
d = 60/13

Like? Yes (3) | No (1)  

Rashi Bansal   9 years AGO

A's Efficiency = 1/12
B's efficiency = 1/12 + 60% of 1/12
= 2/15
efficiency if hey work together= 1/12 + 2/15
= 13/60
time required = 60/13 which is option (6)

Like? Yes (2) | No   

Sundar Kumar   9 years AGO

Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x =
> 8x = 5*12 = > x
= 15/2 days.
A+B=((1/12)+(2/15))=13/60
Therefore , If both of them work together then the number of days required to do the same work is = 60/13
Answer: Option: 6) 60/13

Like? Yes (2) | No   

ranjithreddy   9 years AGO

wild guess

Like? Yes (2) | No   

nishu kumar   9 years AGO

A DO THE WORK 8 DAYS,THEN B DO IT IN 5 DAYS,
THEN IF A DO IT IN 12 DAYS,B DO IT IN 15/2 DAYS
IF BOTH OF THEM WORK TOGETHER THEN NO.OF DAYS REQUIRED TO FINISH THE WORK =1/12+2/15=60/13 DAYS

Like? Yes (2) | No   

Swagatam Kumar Das   9 years AGO

A:B=160:100
=8:5
So, 8:5 :: 12: x
x=15/2
A can do in 1 day 1/12
B can do in 1 day 2/15
So A+B do the job 1/(1/12+2/15) in days
=60/13 days.

Like? Yes (2) | No   

shekhar suman   9 years AGO

Rate of A,Ra=1/12
Rate of B,Rb=1/12+1/12*60/100=2/15
Rate of A+B,Ra+Rb=1/12+2/15=13/60
So, Total no days required=60/13

Like? Yes (2) | No   

shreyansh jain   9 years AGO

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

(A+B)'s 1 day work=(1/12)+[(160/100)(1/12)]
=(1/12)+(2/15)=13/60
So number of days required to complete the same work=60/13

Like? Yes (1) | No   

Biswajit Saha   9 years AGO

Ratio of time taken by A & B= 160:100 = 8:5
Let B takes x days to do the work.
then, 8:5::12:x
x=15/2
Hence A's 1 day work=1/12; B's 1 day work=2/15
(A+B)'s 1 day work=(1/12 + 2/15) = 13/60
Hence A & B together can complete the job in 60/13 days.

Like? Yes (3) | No (2)  

vibhor   9 years AGO

Ratio of times taken by B and A = 160 : 100 = 8 : 5.

Suppose B takes x days to do the work.

8: 5 :: 12 : x
x = (5 x 12)/8
x = 7/2 days.

B will take 7.5 days to complete same work

now,work done by A in one day= 100/12, => 8.33%

work done bt B in one day= 100/7.5,=> 13.33%

work done by A and B in one day= 8.33% + 13.33% => 21.66 %

so total nubmer days required to finish the work= 100/21.66 ,=> 4.61

4.61= 60/13

Ans= 60/13

Like? Yes (3) | No (3)  

rosemary   9 years AGO

A can do work in 12
b is 60% more than A
if A is 100
B is 160
100:160=5:8
to find the time taken by B

5:8:12=12*5/8=60/8=8/60=2/15
total days=1/12+2/15=13/60=60/13.

Like? Yes (2) | No (2)  

Ajinkya Kulkarni   9 years AGO

60/13

Like? Yes (1) | No (1)  

KAMMILI.BALA NAGA BHARGAVI   9 years AGO

A one days work= 1/12
B is 60% more efficient than A
B's one day work = 1/12+(0.6)*1/12=2/15
together can do in= 1/12+2/15=13/60
they complete work in 60/13

Like? Yes (1) | No (1)  

Divyank Dubey   9 years AGO

B is 60 % more efficient than A
so, A=(8/5)B
And, work done in one day by A=1/12
work done in one day by B=2/15
so,1/12+2/15=13/60
total no. of days to complete work=60/13

Like? Yes (2) | No (2)  

Bhanoj   9 years AGO

In a day A can complete 1/12 th part of work, B can complete 1.6/12 th part. Then A+B can do 2.6/12 th of work per day.
So they will take 12/2.6 days to complete. Which is 60/13.

Like? Yes (3) | No (3)  

Jagruti   9 years AGO

Ratio of times taken by A and B = 160 :100 = 8:5
suppose B alone takes x days to do the job.
then, 8:5 =:: 12:x
8x =5*12
x = 7 1/2 days
A and B together can do the work in 1/12 + 2/15 = 13/60
i.e., 60/13 days

Like? Yes (1) | No (2)  

surya   9 years AGO

A work rate = 1/12
B is 60% more efficient than A so B work rate = 1.6/12
total work rate =1/12+1.6/12=2.6/12
time taken for complete the work=12/2.6=60/13

Like? Yes (2) | No (3)  

Abhishek Porwal   9 years AGO

A alone takes 12 days , Now if we calculate the efficiency of B the it will be 12+60% of 12 =19.2
So B alone can do the work in 19.2-12=7.2
Therefore a does the work in 12 days and B does the same work in 7.2 days
So on applying the formula
(a*b)/(a+b) we get 7.6 that is approx 60/13
So the answer is 60/13.

Let me know if this is helpful ?

Like? Yes (1) | No (2)  

Jabez David   9 years AGO

Ratio of time, taken by A and B = 160 : 100 = 8 : 5

If A takes 8 days, B takes 5 days.

If A takes 12 days, B takes = [5/8×12]=15/2 days

Working Together: A+B= 1/12+2/15= 13/60

So, Number days when working together is 60/13 option 6

Like? Yes (1) | No (2)  

Gajula Devendra Babu   9 years AGO

Ratio of times taken by A and B= 160:100=8:5
A can do the same work in 12 days;
then, 8:5=12:x;
x=7+1/2 B can do the same work in 7 and 1/2 days.
Both A and B can do 1 days work=1/12 + 7+1/2=13/60
so, Both A and B can work in 60/13 days.

Like? Yes (1) | No (2)  

ravi prakash   9 years AGO

ratio of theire work=A/B
=160/100
=8/5
now through ration and proporation
8/5=12/x
x=15/2
so work down by B in single day=2/15
and BY A=1/12
NOw work down by both together=1/A +1/B
=13/60
so

=60/13 days to take complete the work

Like? Yes (1) | No (2)  

ANKITA Burbure   9 years AGO

Let A do 100 units work in 1 day.As B is 60% more efficient than A then B can do 160 units in 1 day.A takes 12 days to complete the total units = 12×100=1200. Now the work done by A and B is 100+160=260. Thus no. of days required to complete 1200 units is 1200/260=60/13

Like? Yes (2) | No (3)  

Rishiraj Sengupta   9 years AGO

let a's capacity be 100 then b's capacity is 160
therefore ratio is 160/100 i.e 8/5
now using proportion
8:5::12:x
8x=60
so, x=15/2
combined work 1/12+2/15=60/13

Like? Yes (1) | No (2)  

Sanchit Kapoor   9 years AGO

A's 1 day work = 1/12
Since B is 60% more efficient than A .
So B's 1 day work= 1/12+60% of 1/12 = 8/60
So A and B 's together 1 day work= 1/12+8/60=13/60
Thus number of days=60/13

Like? Yes (2) | No (3)  

SURYA    9 years AGO

since B is 60% more efficient
if A can do a work in 160 days then B can do in 100
then A can do a work in 12 days then B can do=(100/160)*12
=15/2
then the work done when both work togather
=1/(1/12+2/15)=60/13.

Like? Yes (2) | No (4)  

vaitesh mudaliar   9 years AGO

A can do 1/12 work in one day ,while B can do 1/12 + 60% of 1/12 in one day.
let both take x days to finish the work,
if both work together then (work done by A + work done by B ) x = 1
x= 60/13

Like? Yes (2) | No (4)  

Bhavna   9 years AGO

b can do work in 1 day= a's work +60% of a's work=16/120
both can do work in one day=1/12+16/120=26/120
both can do worh in=120/26 days=60/13

Like? Yes (1) | No (3)  

swarupa nuggu   9 years AGO

60/13

Like? Yes (1) | No (3)  

v pavan   9 years AGO

work done by a in 1day(Wa)=(1/12)
work done by b in 1 day(Wb)=(1.6/12)
workdone by both in 1 day= 2.6/12
tota days required= 12/2.6=60/13

Like? Yes (1) | No (3)  

BHASKAR MANDAL   9 years AGO

A one day work = 1/12
B is 60% more efficient than B
=> B one day work = (1/12 + 1/12 * 6/10)
total A+B = 1/12 (2 + 3/5) = 13/60
so the time taken to complete the work = 60/13
so the option is 6

Like? Yes (5) | No (7)  

shubham sethiya   9 years AGO

B can do work in 7.5 days
both can do work in 60/13 days

Like? Yes (1) | No (3)  

lakshmi nalluri   9 years AGO

B=1.6A WHERE A=1/12
B=2/15
A+B=2/15+1/12=13/60 SO,A+B compkete in 60/13 days

Like? Yes (1) | No (3)  

saisudha sarva   9 years AGO

300/65=60/13

Like? Yes (1) | No (3)  

gouthamdaneti   9 years AGO

A capacity =1/12
B capacity=1/12+(60% of 1/12 )
let X=A capacity + B capacity
no.of days = 1/X

Like? Yes (1) | No (3)  

RAKESH   9 years AGO

A = 12 , B = 15/2

1/12 + 2/15 = 13/60 => 60/13 days

Like? Yes (1) | No (4)