Shreya Tiwari   9 years AGO

LET NON ZERO NUMBER =X

X+X^2+X^3+X^4=7380

BY SIMPLFY

X=9

SO A/C TO GIVEN QUESTION "If five power of the number is added to 7380 and divided by the number, then quotient will be?"

SO

(X^5+7380)/X = ((9^5+7380)/9)
=7381
SO QUOTIENT = 7381

Like? Yes (57) | No (7)  

Kushagra Tiwari   9 years AGO

LET NON ZERO NUMBER =X

X+X^2+X^3+X^4=7380

BY SIMPLFY

X=9

SO A/C TO GIVEN QUESTION "If five power of the number is added to 7380 and divided by the number, then quotient will be?"

SO

(X^5+7380)/X = ((9^5+7380)/9)
=7381
SO QUOTIENT = 7381

Like? Yes (45) | No (7)  

P.Pandeeswari   9 years AGO

the non zero number is 9
9+9^2+9^3+9^4=7380
9^5+7380=66429
66429/9=7381.
option:4)7381

Like? Yes (11) | No (4)  

Sanu Panji   9 years AGO

(x^5+x^4+x^3+x^2+x)/x
= x^4+x^3+x^2+x+1
7380+1
=7381

So correct option 4)

Like? Yes (4) | No (3)  

khushboo goenka   9 years AGO

let x+x^2+x^3+x^4=7380
7380+x^5/x=1+x+x^1+x^2+x^3+x^4=7381
so remainder=1
quotient=7381

Like? Yes (1) | No   

CHANDAN KUMAR   9 years AGO

x+x^2+x^3+x^4=7380
x^5+7380/x=x^4+7380/x=7380+1=7381

Like? Yes (1) | No   

ADARSH GAURAV   9 years AGO

7381 is the answer.

Like? Yes (1) | No   

Mohan   9 years AGO

number is 9 ,and ans is 7381,
9+9^2+9^3+9^4=7380 and 9^5+7380=66429
so 66429/9 =7381

Like? Yes (1) | No   

kushagra pareek   9 years AGO

x+x^2+x^3+x^4 = 7380

find (x^5+7380)/x

x^5+x^4+x^3+x^2+x divided by

gives quotient 1+x+x^2+x^3+x^4 which is 7381

Like? Yes (3) | No (2)  

Udhaya kumar   9 years AGO

x+x^2+x^3+x^4 = 7380
x^5+7380 = x^5+x^4 + x^3 + x^2 + x / x
x^4 + x^3 + x^2 + x + 1 = 7381.......

Like? Yes (4) | No (4)  

Chirag Ranjan Lahiri   9 years AGO

Number is 9 and ans is 7381,
9 + 9^2 + 9^3 + 9^4 =7380
and 9^5 +7380 = 66429 so 66429/9 =7381.........

Like? Yes (4) | No (4)  

PAWAN KUMAR   9 years AGO

Let the no be x.
Then, x + x^2 + x^3 + x^4 = 7380
On solving, we get: x=9
Now, 9^5 + 7380 = 59049 +7380 = 66429
66429/9 = 7381 Ans.

Like? Yes (2) | No (3)  

sravani   9 years AGO

x+x^2+x^3+x^4=7380
(x^5+7380)/x=(x^5+x+x^2+x^3+x^4)/x
x(1+x+x^2+x^3+x^4)/x=1+x+x^2+x^3+x^4=1+7380=7381.....

Like? Yes (3) | No (4)  

SUBHASH TULSYAN   9 years AGO

let the no. be x
A/Q
x+x^2+x^3+x^4=7380....(1)
now we have to find
(7380+x^5)/x
=(x+x^2+x^3+x^4+x^5)/x
=x(1+x+x^2+x^3+x^4)/x
=1+x+x^2+x^3+x^4
=1+7380............from(1)
=7381
option(4)

Like? Yes (2) | No (3)  

Rahul Singh   9 years AGO

X+X^2+X^3+X^4 = 7380
X(1+X+X^2+X^3) = 7380
1+X+X^2+X^3 = 7380/X

Now (7380 + X^5)/X = 7380/X + X^5/X
From above = 1+X+X^2+X^3+X^4
= 1+ 7380
= 7381

Like? Yes (2) | No (3)  

Shreya Banerjee   9 years AGO

n+n2+n3+n4 = 7380 (given)
now add n5 to it
and divide that by n,
we wil hv
(n+n2+n3+n4+n5)/n = (1+n+n2+n3+n4) = 7380+1 =
7381

So option 4.

Like? Yes (2) | No (3)  

santosh kumar patel   9 years AGO

x + x^2 + x^3 + x^4 = 7380
then x=9
x^5=66429
then, 66429+7380?9
7381

ans: 7381

Like? Yes (2) | No (3)  

MAHARAJAN.G   9 years AGO

number is 9 ,
sum of its square , cube, four power is 7381, 9+9^2+9^3+9^4=7380
and 9^5+7380=66429 so 66429/9 =7381

Like? Yes (1) | No (2)  

jitu   9 years AGO

9^5=59049+7380

Like? Yes (1) | No (2)  

rajesh reddy   9 years AGO

x+x2+x3+x4=7380,

x+x2+x3+x4+x5= x(1+x+x2+x3+x4)= x(1+7380)

quotient=x(7381)/x

Like? Yes (1) | No (2)  

Anand Dwivedi   9 years AGO

7381

let : X+X^2+X^3+X^4=7380

(X^5+7380)/X = ((9^5+7380)/9) =7381

SO QUOTIENT WILL BE 7381

Like? Yes (1) | No (2)  

niraj   9 years AGO

9*9*9*9*9+7380/9=7381

Like? Yes (1) | No (2)  

Abhishek Vishwakarma   9 years AGO

LET NON ZERO NUMBER =X

X+X^2+X^3+X^4=7380

BY SIMPLFY

X=9

SO A/C TO GIVEN QUESTION "If five power of the number is added to 7380 and divided by the number, then quotient will be?"

SO

(X^5+7380)/X = ((9^5+7380)/9)
=7381
SO QUOTIENT = 7381

Like? Yes (1) | No (2)  

Sanjay Bhatt   9 years AGO

Let the Number be X.
X+X2+X3+X4=7380
(X+X2+X3+X4+X5)/X= 1+X+X2+X3+X4=7381

Like? Yes (1) | No (2)  

Sagar Kharab   9 years AGO

x+x^2+x^3+x^4=7380
now x+x^2+x^3+x^4+x^5=7380 + x^5
x(1+x+x^2+x^3+x^4) / x = 1+x+x^2+x^3+x^4= 1 + 7380

Like? Yes (1) | No (2)  

Y V S Chandrakanth   9 years AGO

x+x2+x3+x4=7380
(7380+x5)/x=(x+x2+x3+x4+x5)/x=1+x+x2+x3+x4=1+7380=7381

Like? Yes (1) | No (2)  

Gagan Goel   9 years AGO

9 + 81 +729+6561=7380
9^5 +7380=66429
66429 / 9=7381

Like? Yes (1) | No (2)  

Rajnikant   9 years AGO

let's assume no.=x
So from ques,
x+x²+x³+x⁴=7380 .......eq. 1

Adding x⁵ with 7380 and dividing it by the no.
= (7380+x⁵)/x
= (x+x²+x³+x⁴+x⁵)/x ......from eq. 1
= x(1+x+x²+x³+x⁴)/x
= 1+x+x²+x³+x⁴
= 1+7380 ......from eq. 1
= 7381

Like? Yes (1) | No (2)  

jagadeesh   9 years AGO

x+X^2+x^3+X^4 = 7380

(X^5+ 7380)/X = X(1+7380)/X = 7381

Like? Yes (1) | No (2)  

Abhishek mani   9 years AGO

9+81+729+6561=7380 (so x=9)
again, (7380+59049)/9=7381
so ans(4)

Like? Yes (2) | No (3)  

NAVEEN KUMAR   9 years AGO

9+9^2+9^3+9^4=7380
9^5+7380=66429
66429/9=7381

Like? Yes (1) | No (2)  

Sahil Nagpal   9 years AGO

let the no be x
so by statement of question x+x^2+x^3+x^4=7380

next statement is (x^5+7380)/x=we have to find

so put the value of 7380 from first in second
therefore, (x^5+x+x^2+x^3+x^4)/x=x^4+1+x+x^2+x^3

1+7380=7381, answer

Like? Yes (1) | No (2)  

ayushi   9 years AGO

By inspection the no. shud be

Like? Yes (1) | No (2)  

pushpa   9 years AGO

x+ x^2 +x^3+ x^4 = 7380

(7380+ x^5)/ x
= (x+ x^2 +x^3+ x^4 + x^5)/ x
=(1+x+ x^2 +x^3+ x^4)
=7381

Like? Yes (1) | No (2)  

prem   9 years AGO

let the no =a
then
a+a2+a3+a4=7381
from GP cf=a
hence by sum of gp
a=9
hence (7380+(9)pow5)/9=7381

Like? Yes (2) | No (3)  

BHASKAR MANDAL   9 years AGO

x+x^2 + x^3 +x^4 +X^5 / x = 7380 + 1 = 7381
option 4

Like? Yes (2) | No (4)  

Sanchit Kapoor   9 years AGO

x+x^2+x^3+x^4=7380
Solving x=9
Now,(9^5+7380)/9=7381

Like? Yes (2) | No (4)  

RAKESH   9 years AGO

x + x^2 + x^3 + x^4 + x^5 / x

= 1 + (x + x^2 + x^3 + x^4)
= 1 + 7380
= 7381

Like? Yes (2) | No (4)  

Surit Datta   9 years AGO

9 square + 9 cube + 9 four power + 9 = 7380
9 five power + 7380 = 66429
66429 / 9 = 7381
That's it.

Like? Yes (1) | No (3)  

Md.Sultan Khichi   9 years AGO

Let a is the no.
a+a^2+a^3+a^4=7380
Now (a+a^2+a^3+a^4+a^5)/a
=1+a+a^2+a^3+a^4=1+7380=7381
Ans ob 4

Like? Yes (2) | No (4)  

Supriya Mondal   9 years AGO

Let the non zero number is a.
So according to the question a+a^2+a^3+a^4=7380
And we have to divide a^5+7380 by a.
So, (a^5+7380)/a
=(a^5+a+a^2+a^3+a^4)/a
=(1+a+a^2+a^3+a^4)
=(1+7380)
=7381
So answer will be 4)7381

Like? Yes (1) | No (3)  

Abhishek Porwal   9 years AGO

Consider the non zero digits i.e. from 9 to 1
Consider 9 and here is your answer 7381

Like? Yes (1) | No (3)  

DIPAK TIWARI   9 years AGO

(9)+ (9)^2 +(9)^3 +(9)^4 =7380
Hence ,{(9)^5 + 7380 }/9 =7381
Quotient=7381
Option 4

Like? Yes (1) | No (3)  

ravi prakash   9 years AGO

9+9^2+9^3+9^4+9^5=7380+59049
=66429/9
=7381

Like? Yes (1) | No (3)  

Swagatam Kumar Das   9 years AGO

Let the no is x
So x(1+x+x^2+x^3)=7380
so (1+x+x^2+x^3)=7380/x
and the quient will be (7380+x^5)/x
=x^4+7380/x
=x^4+(1+x+x^2+x^3)
=1+7380 =7381

Like? Yes (1) | No (3)  

Tark Patel   9 years AGO

Let number be x

by solving x + x^2 + x^3 + x^4 = 7380 we get x = 9

Then ( 9^5 + 7380 ) / 9 we get 7381.

Like? Yes (1) | No (3)  

VIKRAM KUMAR MAHTO   9 years AGO

7380 a bit greater than 9^4 and almost double of 8^4 . So the single digit number is 9.
Now, 9+91+81+729+6561=7380
Now dividing 9+91+81+729+6561+59049 will give quotient as 9^0+9^1+9^2+9^3+9^4=7380 + 1 =7381

Like? Yes (1) | No (3)  

pragya   9 years AGO

Ans is 7381

x+ x^2 + x^3 + x^4 = 7380 ------(1)

((x^5)+7380)/x=quotient ---------(2)

i tried hit & trial method fr this ques

putting x=10, we get

x^4=10000 which is greater than 7380. So, x must be less than 10.

put x=9,

(9^4)=6561 which is less than 7380
9+(9^2)+(9^3)+(9^4)=7380
hence, x=9

now, put x=9 in eqn (2), we get

quotient=[ (9^5) + 7380 ] / 9 = 7381

Like? Yes (1) | No (3)  

Anoop Tiwari   9 years AGO

Number is 9, because
9+9^2+9^3+9^4=7380
and 9^5=59049
So 9^5+7380=66429
66429/9=7381

Like? Yes (1) | No (3)  

Anshul Shrivastava   9 years AGO

Given x+x^2+x^3+x^4=7380,
now,
(x+x^2+x^3+x^4+x^5)/x
=>1+x+x^2+x^3+x^4....... (eqn 1)
now from the que.
x+x^2+x^3+x^4=7380 putting in eqn 1
we get,
=1+7380
=7381 ans.

Like? Yes (1) | No (3)  

A SIRISHA    9 years AGO

LET NON ZERO NUMBER =X

X+X^2+X^3+X^4=7380

BY SIMPLFY

X=9

SO A/C TO GIVEN QUESTION "If five power of the number is added to 7380 and divided by the number, then quotient will be?"

SO

(X^5+7380)/X = ((9^5+7380)/9)
=7381
SO QUOTIENT = 7381

Like? Yes (1) | No (3)  

Ajinkya Kulkarni   9 years AGO

(x+x2+x3+x4+x5)/x=1+x+x2+x3+x4=1+7380=7381

Like? Yes (1) | No (3)  

shubham   9 years AGO

n+n2+n3+n4 = 7380 (given) nw add n5 to it and divide that by n, we wil hv (n+n2+n3+n4+n5)/n = (1+n+n2+n3+n4) = 7380+1 = 7381

Like? Yes (1) | No (3)  

RAMAKRISHNA   9 years AGO

the number is 9
9+9^2+9^3+9^4+9^5=66429
66429/9=7381

Like? Yes (1) | No (3)  

Parag   9 years AGO

i just found out the closest x^4 to 7380
i tried x=10 so x^4=10000 so that means x

Like? Yes (1) | No (3)  

bhavna singh   9 years AGO

when the number is divided, one time power gets cancelled and the number is incremented once

Like? Yes (1) | No (4)  

Rahul   9 years AGO

Suppose the number is x

Then x = 1 + 7380 = 7381

Like? Yes (1) | No (5)  

Ranjit Somisetty   9 years AGO

x*(1+x+x2+x3+x4)/x= 1+7380

Like? Yes (1) | No (6)