What is the next number of the following sequence 13, 34, 74, 170, 290, ..............

Supriya Mondal   9 years AGO

Here, the numbers are addition of two consecutive prime number's square.
1st term=2^2+3^2=13
2nd term=3^2+5^2=34
3rd term=5^2+7^2=74
4th term=7^2+11^2=170
5th term=11^2+13^2=290
So, next term will be=13^2+17^2=458
So, option 4)458 is the right answer

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Santhoshkumar   9 years AGO

Prime number square,
2^2+3^3=13
5^2+3^2=34
7^2+5^2=74
11^2+7^2=170
13^2+11^2=290
17^2+13^2=458

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RAKESH   9 years AGO

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458

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Surit Datta   9 years AGO

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458
the series is summation of two consecutive prime number
starting from 2
so option 4
that's it.

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JANARTHANAN RAM   9 years AGO

prime no^2+(next prime no^2)
2^2+3^2=13;
3^2+5^2=34;
'..
..
13^2+17^2=458

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sunilbaba    9 years AGO

s

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Chandu Reddy   9 years AGO

2^2+3^2=13,3^2+5^2=34,5^2+7^2=74,7^2+11^2=170, 11^2+13^2=290,13^2+17^2=458

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Anshul Garg   9 years AGO

13 = 4 + 9 = 2^2 + 3^2
34 = 9 + 25 = 3^2 + 5^2
74 = 25 + 49 = 5^2 + 7^2
170 = 49 + 121 = 7^2 + 11^2
290 = 121 + 169 = 11^2 + 13^2

From the above, we can conclude that the number is addition of square of lager prime number in previous and the square of next prime number.

And, Hence the next number will be 169 + 289 = 458

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Jaspalsingh Parmar   9 years AGO

Option 4 is correct

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mahi reddy   9 years AGO

2^2+3^2=13,
3^2+5^2=34,
5^2+7^2=74,
7^2+11^2=170,
11^2+13^2=290,
13^2+17^2=458

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Testing Account   9 years AGO

2*2 3*2,3*2 5*2,5*2 7*2,7*2 11*2, 11*2 13*2,13*2
17*2=458

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praveen kumar   9 years AGO

17^2+13^2

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Sravanthi   9 years AGO

2^2+3^2=13
3^2+5^2=34
sum of squres of primary numbers

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ABHINAV PUSHPAM   9 years AGO

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458
So, option 4) is correct

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MRITUNJAY   9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

option 4.

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RAHUL KUMAR   9 years AGO

Ans is 458

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458 .........ANS

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Abhishek Sumit   9 years AGO

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458

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Dharmraj Sharma   9 years AGO

2^2 + 3^2 =13
3^2 + 5^2 =34
5^2 + 7^2 =74
7^2 + 11^2 =170
11^2 + 13^2=290
13^2 + 17^2=458

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Abhishek birkh   9 years AGO

2^2+3^2,3^2+5^2,5^2+7^2

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ramakrishnateja   9 years AGO

the given numbers are the sum of squares of the prime numbers. they are as follows:
13=3^2+2^2
34=5^2+3^2
74=7^2+5^2
170=11^2+7^2
290=13^2+11^2
so the next number is 458=17^2+13^2

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Subhadip Samanta   9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
the next prime no of 13 is 17
:The next term in the series is(13^2+17^2)=458 (option 4)

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Rabindra Prasad Modi   9 years AGO

sum of two consecutive prime numbers everytime

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jaganmohan rao .pola   9 years AGO

prime numbers: 2,3,5,7,11,13,17,...............

2^2+3^2 = 13
3^2+5^2 = 34
5^2+7^2 = 74
7^2+11^2 = 170
11^2+13^2 = 290
13^2+17^2 = 458

Ans:458

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KUMAR HARSH   9 years AGO

because all are the addition of two squared number like
2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
so next is by option 13^2+17^2=458

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vishal kumar   9 years AGO

2^2 + 3^2 = 13
3^2 + 5^2 = 34
5^2 + 7^2 = 74
7^2 + 11^2 = 170
11^2 + 13^2 = 290
13^2 + 17^2 = 458 ....... this is the answer

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Ajinkya Kulkarni   9 years AGO

sum of squares of adjacent prime numbers

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Jitendra Prasad   9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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ADARSH GAURAV   9 years AGO

458 is the answer

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b.subbarao   9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290 so 13^+17^2=458

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Saurabh Soni   9 years AGO

half of the numbers nd thn subtract them..The ans is thn doubled to get d next no.

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Neha Giri   9 years AGO

Here all are two successive prime no squares addition, i.e.
13=2^2+3^2
34=3^2+4^2
74=5^2+7^2
170=7^2+11^2
290=11^2+13^2
so,next will be
13^2+17^2=458.

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Aishwariya    9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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A M ANKIT KALLURAYA   9 years AGO

each number is the sum of square of prime numbers.
2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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Tark Patel   9 years AGO

-> 13 , 34 , 74 , 170 , 290

-> (2^2 + 3^2) , (3^2 + 5^2) , (5^2 + 7^2) , (7^2 + 11^2) , (11^2 + 13^2) so next will be = (13^2 + 17^2)

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pravallika   9 years AGO

3^2+2^2;5^2+3^2;7^2+5^2;11^2+7^2;13^2+11^2;17^2+13^2=13,34,74,170,290,458(sum of squares of primenumber and its preceeding prime)

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tasho k   9 years AGO

Addition of squares of consecutive prime numbers....

Square of 13 + square of 17 = 169+289=458

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sandeep kumar   9 years AGO

3^2+2^2=13

5^2+3^2=34

similarly ..

next prime no.^2+previous prime no.^2 = ANS...................



ANS = 458

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DHEERAJ KUMAR   9 years AGO

we are adding sq. of continuous two prime numbers like 2sq+3sq, 3sq+5sq, 5sq+7sq., 7sq+11sq, 11sq+13sq and finally 13sq+17sq= 458

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POOJA SINGH   9 years AGO

2^2 +3^2=13
3^2 +5^2=34
5^2 + 7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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arush gupta   9 years AGO

answer is 458
square and add 2 consequent prime numbers 2 3 5 7 11 13 17
2^2+3^2 =13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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Mohak Jain   9 years AGO

consecutive two prime nos squared and added.
eg:
2^2+3^2, 3^2+5^2,....... 17^2+13^2

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nitya   9 years AGO

2^2+3^2=13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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Akshat Kapoor   9 years AGO

answer is 458
square and add 2 consequent prime numbers 2 3 5 7 11 13 17
2^2+3^2 =13
3^2+5^2=34
5^2+7^2=74
7^2+11^2=170
11^2+13^2=290
13^2+17^2=458

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Paras Jain   9 years AGO

its 458..

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