x, y and z are three positive integers such that x not= y not= z and 0 < x < y < z < 10; If x+y+z =

Yathiraj   9 years AGO

since 0 < x < y < z < 10,
x range 1 to 7
y range 2 to 8
z range 3 to 9

considering the above range and with different combination of x, y, z where x+y+z=15, you will get 8 such pairs of (x,y,z).

x:1, y:5, z:9
x:1, y:6, z:8
x:2, y:4, z:9
x:2, y:5, z:8
x:2, y:6, z:7
x:3, y:4, z:8
x:3, y:5, z:7
x:4, y:5, z:6

So, Option 8.

Like? Yes (7) | No (1)  

Santosh Kumar   9 years AGO

if x=1then possible (y,z)={5,9 & 6,8}
if x=2then possible (y,z)={4,9 & 5,8 &6,7}
if x=3then possible (y,z)={4,8 & 5,7}
if x=4then possible (y,z)={5,6 }
so total=8

Like? Yes (4) | No (1)  

SAKTHEESVARI S   9 years AGO

the only possibilities are, x,y,z are
1,5,9; 1,6,8; 2 4 9; 2 5 8; 2 6 7; 3 4 8; 3 5 7; 4 5 6;
totally 8 possibilities

Like? Yes (3) | No   

Supriya Mondal   9 years AGO

There are 8 possible pairs and they are-
(1,5,9)
(1,6,8)
(2,4,9)
(2,5,8)
(2,6,7)
(3,4,8)
(3,5,7)
(4,5,6)
so, option 8)8 is the right answer

Like? Yes (3) | No   

Kaju Gupta   9 years AGO

(x,y,z)
(1,5,9)
(2,4,9)
(1,6,8)
(2,5,8)
(3,4,8)
(2,6,7)
(3,5,7)
(4,5,6)

Like? Yes (3) | No (1)  

kunal   9 years AGO

(1,5,9),(1,6,8),(2,4,9),(2,5,8),(2,6,7),(3,4,8),(3,5,7),(4,5,6)

Like? Yes (2) | No   

A.SOMA SUNDARI   9 years AGO

the is only possibilities are
1+5+9
1+6+8
2+4+9
2+5+8
2+6+7
3+4+8
3+5+7
4+5+6

Like? Yes (3) | No (1)  

praveen kumar   9 years AGO

8 pairsare possible

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KUMAR HARSH   9 years AGO

cobination is(4,5,6),(3,5,7),(3,4,8),(2,4,9),(2,5,8),(2,6,7),(1,5,9),(1,6,8)

Like? Yes (2) | No (1)  

Sravanthi   9 years AGO

1 5 9
1 6 8
2 5 8
2 4 9
2 6 7
2 6 7
3 5 7
3 4 8
4 5 6

Like? Yes (2) | No (1)  

Dharmraj Sharma   9 years AGO

for 0

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harvinder   9 years AGO

1,5,9
1,6,8
2,6,7
2,5,8
2,4,9
3,5,7
3,4,8
4,5,6

Like? Yes (2) | No (1)  

MD SOHAIL AKHTER   9 years AGO

951,942,861,852,843,762,753,654

Like? Yes (2) | No (1)  

Dorababu M   9 years AGO

possible pairs are
1,5,9
1,6,8
2,4,9
2,5,8
2,6,7
3,4,8
3,5,7
4,5,6

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anusha   9 years AGO

ans is 8

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RAKESH ARYA   9 years AGO

1. 1,5,9
2. 1,6,8
3. 2,4,9
4. 2,5,8
5. 2,6,7
6. 3,4,8
7. 3,5,7
8. 4,5,6

Like? Yes (2) | No (1)  

jaganmohan rao .pola   9 years AGO

8

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nitin kishore   9 years AGO

The pairs which satisy all the conditions are:-
(1,5,9), (1,6,8), (2,4,9),(2,5,8),(2,6,7),(3,4,8),(3,5,7),(4,5,6)

Like? Yes (1) | No   

shovan Manna   9 years AGO

let x=1,then y and z must be y=5,z=9,
y=6,z=8
when x=2,then y and z must be y=5,z=8
y=6,z=7,y=4 and z =9
when x=3 then y and z must be y=4,z =8
y=5,z=7
when x=4 then y and z must be y=5,z =6

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SANDHYA KALIGITHI   9 years AGO

(1,5,9), (2,4,9),
(1,6,8), (2,5,8), (3,4,8),
(2,6,7), (3,5,7),
(4,5,6)

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Modadugu vishnu kumar   9 years AGO

According to the given condition 0

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POOJA SINGH   9 years AGO

all possible values of x y z that satisfy the condition x + y + z equals to 15 is (1,5,9)(1,6,8)(2,6,7)(2,4,9)(2,5,8)(3,4,8)(3,5,7)(4,5,6). so answer is 8

Like? Yes (1) | No   

Pranati Kundu   9 years AGO

(1,5,9)(1,6,8)(2,6,7)(2,4,9)(2,5,8)(3,4,8)(3,5,7)(4,5,6) r the 8 pairs

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Priyanka Shete   9 years AGO

Possible pairs are-
(1,5,9),
(2,5,8),
(3,5,7),
(4,5,6),
(2,4,9),
(3,5,8),
(2,6,7),
(1,6,8).

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Revathi Perapu   9 years AGO

possible pairs are 8

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Jaspalsingh Parmar   9 years AGO

Option 8 is correct

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KALYAN KUMAR REDDY VALLURU   9 years AGO

starting with 1-2
starting with 2-3
starting with 3-2
starting with 4-1
total 8

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Preethi   9 years AGO

8 possible pairs are 1,5,9
2 ,4,9
1,6,8
2,5,8
3,4,8
2,6,7
3,5,7
4,5,6

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sindhura   9 years AGO

Given that x not= y not= z and 0 < x < y < z < 10; also x+y+z=15
Among x, y and z, z is greater but less than 10, so z=9, 8, 7, 6 only for remaining values given condition violates.
So the combinations are (2,4,9),(1,5,9),(1,6,8),(2,5,8),(3,4,8),(2,6,7),(3,5,7),(4,5,6)
Answer is 8 combinations.

Like? Yes (1) | No   

PIYUSH KUMAR   9 years AGO

1+5+9=15
1+6+8=15
2+4+9=15
2+5+8=15
2+6+7=15
3+4+8=15
3+5+7=15
4+5+6=15

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Arvind gupta   9 years AGO

Answer is 8 combinations
you can run this "C" program
#include
int main(){
int x,y,z,max=10;
for(x=1;x

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Sambar Naresh   9 years AGO

8 psbl pairs are 1,5,9 1,6,8 2,4,9 2,5,8 2,6,7 3,4,8 3,5,7 4,5,6

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Swathy Murugan   9 years AGO

Total combinations available is 8

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Thirupathi Reddy   9 years AGO

The possible sets are (1,5,9) (1,6,8)(2,4,9)(2,5,8)(2,6,7)(3,4,8)(3,5,7)(4,5,6)

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E. UDAY REDDY   9 years AGO

(1,5,9) ->(1,6,8)
(2,5,8)->(2,4,9)->(2,6,7)
(3,5,7)->(3,4,8)
(4,5,6)

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Divya jain   9 years AGO

possible values for x,y,z
(2,4,9)
(1,5,9)
(2,5,8)
(1,6,8)
(3,4,8)
(2,6,7)
((3,5,7)
(4,5,6)

Like? Yes (1) | No   

sandeep ramchandra pawaskar   9 years AGO

9+2+4=15
9+1+5=15
8+4+3=15
8+2+5=15
8+6+1=15
7+5+3=15
7+6+2=15
6+5+4=15

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ayushi   9 years AGO

pairs are :
(1,5,9);(1,6,8);
(2,4,9);(2,5,8);(2,6,7);
(3,4,8);(3,5,7);
(4,5,6);

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Paras Jain   9 years AGO

Ans => 8

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Shanmugapriya.G   9 years AGO

possible combination is 8.
do it by trial method.

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rajkumar   9 years AGO

according to given conditions
possible pairs are
(1,6,8)
(1,5,9)
(2,4,9)
(2,5,8)
(3,4,8)
(3,5,7)
(4,5,6)
(2,6,7)

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NANGINEDI RAVITEJA   9 years AGO

for z=9 it as 942,951
z=8 it as 852,843,861
Z=7 then 753 ,762, z=6 then 654 as z,y,x values as possible

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Ramesh Bathula   9 years AGO

the chances are
(1,5,9) (1,6,8) (2,4,9) (2,5,8) (2,6,7) (3,4,8) (3,5,7) (4,5,6)

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ganesh babu   9 years AGO

(1,5,9)
(2,4,9)
(1,6,8)
(2,5,8)
(3,4,8)
(2,6,7)
(3,5,7)
(4,5,6)

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Ravi   9 years AGO

(1,5,9),(1,6,8),(2,4,9),(2,5,8),(2,6,7),(3,4,8),(3,5,7),(4,5,6)

Like? Yes (1) | No   

mubarak   9 years AGO

1,6,8
1,5,9
2,4,9
2,5,8
2,6,7
3,4,8
3,5,7
4,5,6

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nagaprasad   9 years AGO

cause

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sudhakar   9 years AGO

1)1+5+9=15
2)1+6+8=15
3)2+4+9=15
4)2+5+6=15
5)2+6+7=15
6)3+5+7=15
7)3+4+8=15
8)4+5+6=15
so answer is option 8

Like? Yes (1) | No   

Surit Datta   9 years AGO

the possible pairs are
(1,5,9)
(1,6,8)
(2,5,8)
(2,4,9)
(2,6,7)
(3,5,7)
(3,4,8)
(4,5,6)
so option 8
that's it.

Like? Yes (1) | No   

Vipul Kumar Paliwal   9 years AGO

with 9...only 2 possibilities...ie.9+5+1 and 9+4+2
with 8...8+6+1..8+5+2...8+4+3
with 7..7+6+2....7+5+3
with 6....6+5+4

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MRITUNJAY   9 years AGO

(1,5,9)
(1,6,8)
(2,6,7)
(2,4,9)
(2,5,8)
(3,4,8)
(3,5,7)
(4,5,6)

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RAHUL KUMAR   9 years AGO

159
168
249
258
267
348
357
456
Option 8 is r8.

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haneesha   9 years AGO

the combinations are (1,5,9) (1,6,8) (2,6,7) (2,5,8) (2,4,9) (3,5,7) (3,4,8)(4,6,5)

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ABHINAV PUSHPAM   9 years AGO

159
168
249
258
267
348
357
456
These are possible sets
So option 8)

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T.Aravinth kumar   9 years AGO

only 8 possible pairs

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nikhil   9 years AGO

159,168
249,258,267
348,357
456

Like? Yes (1) | No   

Anil Beck   9 years AGO

According to condition
x must be in between 1,2,3,4
y must be in between 4,5,6
z must be in between 6,7,8,9
So possible values are
x-y-z

1-5-9
1-6-8
2-4-9
2-5-8
2-6-7
3-4-8
3-5-7
4-5-6

Like? Yes (1) | No   

SARAVANAN S K   9 years AGO

1+5+9=15
2+5+8=15
3+5+7=15
4+5+6=15
1+6+8=15
2+7+6=15
3+8+4=15
2+4+9=15

Like? Yes (1) | No   

Harish Reddy Namala   9 years AGO

The pairs are (1,5,9), (1,6,8), (2,4,9), (2,5,8), (2,6,7), (3,4,8) ,(3,5,7),(4,5,6)

Like? Yes (1) | No (1)