Supriya Mondal   9 years AGO

We know that for rhombus,
Side=(1/2)*√(diagonal 1*diagonal 1+diagonal 2*diagonal 2)
Here, side=5 m and diagonal 1=8 m
After putting the above value on the formula we get,diagonal 2=6 m

Like? Yes (19) | No (10)  

mohsin   9 years AGO

Diagonals of rhombus bisect n divide equally. . there fore

5^2= 4^2 + X^2 (phytagoras theorem)

25-16= x^2

x=3

other diagonal=3+3=6

Like? Yes (11) | No (2)  

praveen kumar   9 years AGO

half lenth of other diagonal = sqrt(5^2 -4^2) = 3
so full length = 2 *3 = 6 m

Like? Yes (6) | No (3)  

SUSHANT KUMAR   9 years AGO

p=sqrt(4a^2-q^2)
here a=5
and q=8 hence p=6m ans

Like? Yes (6) | No (4)  

GourabDeb   9 years AGO

side = 5 m
1st diagonal = d1 = 8 m

(d2 /2 )^ 2=side ^ 2 - (d1/2 )^ 2 = 25-16 = 9
d2 = 2* 3 =6

Like? Yes (4) | No (2)  

sompon temtheerakij   9 years AGO

from pythagorus
5^2 = 4^2 + x^2
x= 3
diagonal = 6

Like? Yes (2) | No (1)  

RAJAN   9 years AGO

length of diagonal =2[{ 5^2 - (8/2)^2}^1/2]

Like? Yes (3) | No (2)  

iswarya revuru   9 years AGO

p = √( 2a2 - 2a^2 cos(A) )

Like? Yes (2) | No (2)  

Gaurav Kumar   9 years AGO

since diagonals are perpendicular to each other, so through Pythagoras theorem we can find the half of the other diagonal to be 3m, thus the total length of the diagonal would be 6m

Like? Yes (3) | No (3)  

ramakrishna   9 years AGO

d2=sqrt(4a^2-d1^2)

Like? Yes (3) | No (3)  

mohit chugh   9 years AGO

25=16+x^2
x=3
length=6

Like? Yes (3) | No (3)  

Vishakha Tinkhede   9 years AGO

(1st diagonal)^2 + (2nd diagonal)^2 = 4(a^2) where a is the side of rhombus...and hence 64+(2nd diagonal)^2 = 25*4=100
=> 2nd diagonal =6m

Like? Yes (3) | No (3)  

GIRISH TYAGI   9 years AGO

other diagonal will be 3*2=6 because first diagonal is = 8 now we know that diagonals of a rhombus intersect at mid point and at perpendicular also so half of 8 = 4 and one side of rhombus 5 which will be hypotaneous so other half side of that right angled triangle will be 3 now the full diagonal will be 3*2 =6

Like? Yes (2) | No (2)  

sandeep ramchandra pawaskar   9 years AGO

option 4 is correct

Like? Yes (1) | No (1)  

KUMAR HARSH   9 years AGO

side^2=(1'st daigonal/2)^2+(2'nd daigonal/2)^2
5^2=(8/2)^2+(2'nd daigonal/2)^2
25=16+(2'nd daigonal/2)^2
9=(2'nd daigonal/2)^2
3=(2'nd daigonal/2)
2'nd daigonal=3*2=6

Like? Yes (1) | No (1)  

PRASHANT KUMAR   9 years AGO

Length=2(25-16)^0.5

Like? Yes (1) | No (1)  

siddharth prakash singh   9 years AGO

length of side is 5m and diagonals of rhombus bisect each other at 90 degree. hence a right triangle will be formed. having two sides 4m and 5m hence other side will be 3m. thus other diagonal will be 6m

Like? Yes (1) | No (1)  

NANGINEDI RAVITEJA   9 years AGO

by using triangle we get another diagonal as 3+3 =6

Like? Yes (1) | No (1)  

jaganmohan rao .pola   9 years AGO

6

Like? Yes (1) | No (1)  

Bikash sahu   9 years AGO

5^2-4^2=3
3*2=6

Like? Yes (1) | No (1)  

ZAHEER   9 years AGO

100 = 64+d^2

Like? Yes (1) | No (1)  

Josepheena Joseph   9 years AGO

the diagonals of a rhombus bisect at right angles

Like? Yes (1) | No (1)  

Pranati Kundu   9 years AGO

4*side^2=d1^2+d2^2
d2=6 m

Like? Yes (2) | No (2)  

Thirumalesh   9 years AGO

according to phytogurus theorem

Like? Yes (2) | No (2)  

karthik hariharan   9 years AGO

The diagonals bisect at 90 degree.
Therefore, 5²-x²=4²
x²=9
Therefore, x=3cm.
2x=6cm.
Therefore, the other diagonal is 6cm.

Like? Yes (1) | No (1)  

RAVI KUMAR   9 years AGO

since diagonal of rhombus bisect at 90 degree
then let half of second diagonal is x
x^2+4^2=5^2
x^2=25-16
x=3
length of diagonal=2*x
=>6m

Like? Yes (1) | No (1)  

lakshmi narayana   9 years AGO

its right angle triangle 3
3+3=6

Like? Yes (1) | No (1)  

shafeeja mp   9 years AGO

x=square root (5^2-4^2)=3
so x=2*3=6

Like? Yes (1) | No (1)  

MRITUNJAY   9 years AGO

4*a^2=p^2+q^2
where a =side of rhombus
p,q diagonal of rhombus
4*5*5=8*8+q*q
100-64=q^2
q^2=36
q=6m

Like? Yes (1) | No (1)  

dilip kumar   9 years AGO

8*8+d*d=4*5*5=>d=6

Like? Yes (1) | No (1)  

shareef   9 years AGO

5^2 - 4^2 = x ^2
(x/2) = 3
x=6

Like? Yes (2) | No (2)  

rakhi kumari   9 years AGO

2*((5^2-4^2)^1/2)

Like? Yes (1) | No (1)  

mukund   9 years AGO

diagonals of rhombus bisect each other at right angle. so one side of rhombus and the half of the diagonals make a right angle triangle. (5^2-4^2)^(1/2) =3 so answer is 3*2.

Like? Yes (1) | No (1)  

vivek   9 years AGO

as diagonals of the rhombus bisects each other and using pythagoras theorem.....6

Like? Yes (1) | No (1)  

Misti Kumar   9 years AGO

25-16=9=3^2
3*2=6m

Like? Yes (1) | No (1)  

Surabhi Mishra   9 years AGO

If length of diagonals are d1 & d2 and side is a
d1^2 +d2^2 = 4(a)^2

8^2 + d2^2 = 4*(5)^2
64+d2^2 = 4*25
64+d2^2=100
d2^2=100-64
d2^2=36
d2=6m

ans- 4) 6m

Like? Yes (1) | No (1)  

nitin kishore   9 years AGO

other diagonal is: 2*sqrt(25-16)

Like? Yes (2) | No (3)  

KALYAN KUMAR REDDY VALLURU   9 years AGO

Using Pythagorean theorem,
the other diagonal = 2*sqrt((5)^2-(4)^2)
which is 6m.

Like? Yes (1) | No (2)  

Gurram Mahendra ranganath   9 years AGO

side=sqrt(diag1length^2 + diag2length^2)/2

Like? Yes (1) | No (2)  

Altaf Hussain   9 years AGO

1/2*d1*d2=Area of all triangles in Rhombus
d1 - diagonal 1
d2 - diagonal 2

Like? Yes (1) | No (2)  

sravani   9 years AGO

let a be the sided and p,q are the diagonals
then a,p are given so q=sqrt(4a^2 - p^2)
so,q=6.

Like? Yes (1) | No (2)  

Meenakshi   9 years AGO

Length of the rhombus
a=1/2 * sqrt(d1^2+d2^2)
=>a^2=1/4 * (d1^2+d2^2)
=>25=1/4 * (64+d2^2)
=>100=64+d2^2
=>36=d2^2
=>6=d2
so,length of the other diagonal is 6 m

Like? Yes (1) | No (2)  

Yallapu Uday tarun kumar   9 years AGO

side=sqrt(((diagonal1)/2)^2+((diagonal2)/2)^2)
5=sqrt(4^2+X^2)
x=3
diagonal2=2*x=6m

Like? Yes (1) | No (2)  

Satwik Bahatam   9 years AGO

calculated using pythagroes formulae

Like? Yes (1) | No (2)  

sindhura   9 years AGO

(d1)^2+(d2)^2=4(a)^2 => d2=6m

Like? Yes (2) | No (3)  

Satya B   9 years AGO

let diagonal be x
x^2 + 8^2 = 4 * 5^2
x^2 + 64 = 100
x^2 = 36
x=6

Like? Yes (1) | No (2)  

Surit Datta   9 years AGO

let a be the length of the sides of the rhombus
and d1 , d2 are the diagonals of it.
we know the formula,
as,
d1^2 + d2^2 = 4*a^2
putting the values here,
a = 5m
d1 = 8m
we get,
d2 = 6m
so option 4
that's it.

Like? Yes (4) | No (5)  

PAWAN KUMAR   9 years AGO

Since the diagonals of a rhombus intersect each other at right angles, so
hypotenuse = 5cm
perpendicular = 8/2 = 4 cm
So, base = 3 cm
Therefore, length of other diagonal = 2*3 = 6 cm. Ans

Like? Yes (1) | No (2)  

darshana kumrawat   9 years AGO

half of 1 diagonal =4
half of secondiagonal = sqrt(5^2 - 4^2)= 3
thus length of diagonal= 6

Like? Yes (4) | No (5)  

Jay parmar   9 years AGO

5^2 = 3^2 + 4^2
so
next diagonal is 6 m

Like? Yes (1) | No (2)  

Sunil Chavan   9 years AGO

by using this formula (d1)^2+(d2)^2=4a^2
where d1 &d2 are the length of the diagonals and a is the side of the rhombus

Like? Yes (1) | No (2)  

aman aditya   9 years AGO

Using heron's formula
12=(1/4)*x*(100-x*x)^1/2
X=6

Like? Yes (1) | No (2)  

Srinivas   9 years AGO

half of diagonal is 4,
then it forms a right angle triangle with sides?,4,5 then other side is half of another diagonal which is 3..then the other diagonal length is 6

Like? Yes (2) | No (3)  

madhusudhana   9 years AGO

Using Rhombus properties and Pythagorean theorem

Like? Yes (2) | No (3)  

Yathiraj   9 years AGO

Diagonals are perpendicular.
Hence, the side of the Rhombus becomes Hypotenuse of a right angle triangle.
By applying pythagoras theorem,
the half of the other diagonal will be
5^2 = Sqrt(4^2 + b^2) => b=3m (half of the other diagonal)
Hence, the full length of diagonal will be 3x2=6m.

Option 4.

Like? Yes (6) | No (7)  

Pragati Rode   9 years AGO

The diagonals meet in the middle at a right angle.
All sides of rhombus are equal i.e. 5m
(Side)^2=(half of one diagonal)^2+(half of second diagonal)^2
by using this formula
(5)^2=(4)^2+(half of second diagonal)^2
half of second diagonal=3
second diagonal=6m

Like? Yes (4) | No (5)  

KIRUBA S   9 years AGO

length of a side of rhombus is 5m and one of its diagonals is of length 8m

Like? Yes (1) | No (2)  

shivom pandey   9 years AGO

as the dioganal bisect vertex angle and the are perpendicular to each other that's why using pythagoras theorem we will get the half length of diagonal which vcomes to be 3

Like? Yes (1) | No (2)  

Madhumoy Gope   9 years AGO

Diagonal length=2*((5^2-4^2)^0.5=2*(9^0.5)=6m
So,option (4) is correct

Like? Yes (1) | No (2)  

RAKESH   9 years AGO

d = 2 * (5^2 - 4^2)^(.5) = 6m

Like? Yes (1) | No (3)  

ABHINAV PUSHPAM   9 years AGO

Answer is 6

Like? Yes (1) | No (3)  

Samyak   9 years AGO

diagonal lenth is 8 m and side is 5m
Sohalf lengfth is
(x)2 +(4)2 = (5)2
So, (x)2 = 9
So x = 3;
but totla diagonal length is 3+3 is 6.

Like? Yes (2) | No (4)